3 moles of water vapor at 110 °C was heated to 140 °C in a constant volume container, and the pressure of water vapor in the final conditions was calculated to be 1 atm. Then, the container was changed to a constant pressure container (external pressure = 1 atm) and the volume of the gas was increased 3-fold under these conditions without any heat exchange. What is the change in the internal energy of the system. (For water vapor c = 2.01 J g-' K-").

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Moles of water vapor at 110 °C was heated to 140 °C in a constant volume container, and the pressure of water vapor in the final conditions was calculated to be 1 atm. Then, the container was changed to a constant pressure container exchange. What is the change in the internal energy of the system.

(For water vapor c=2.01 J g-1 K-1)

3 moles of water vapor at 110 °C was heated to 140 °C in a constant volume container, and the pressure of water vapor
in the final conditions was calculated to be 1 atm. Then, the container was changed to a constant pressure container
(external pressure = 1 atm) and the volume of the gas was increased 3-fold under these conditions without any heat
exchange. What is the change in the internal energy of the system.
(For water vapor c = 2.01 J g-' K-")
%3D
Transcribed Image Text:3 moles of water vapor at 110 °C was heated to 140 °C in a constant volume container, and the pressure of water vapor in the final conditions was calculated to be 1 atm. Then, the container was changed to a constant pressure container (external pressure = 1 atm) and the volume of the gas was increased 3-fold under these conditions without any heat exchange. What is the change in the internal energy of the system. (For water vapor c = 2.01 J g-' K-") %3D
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