22ln an Electrolytic cell with Fe and Sn electrodes, calculate the E°ce knowing thatFe*3+ e => Fe*2 E°= 0.771 Vand Sn2*+ 2e => SnE°= - 0.14 V.O a. 0.627 VO b. - 0.627 VO c. 0.911 VO d. -0.911 V10Which is incorrect for minimizing the decomposition of Sodium thiosulfate solutionsO a. Adjust the pH (9-10)O b. Standard solutions of reagents are prepared under sterile conditionsOc The presence of bactericides, such as chloroform, sodium benzoateO d. Standard solutions of reagents are prepared in absence of oxygen24 In the reactionCe* + Fe2* è Ce + Fe*Knowing that Fe + e ==> Fe*2 E= 0.767 VCe* +e ==> Ce3 E= 1.70 VAnd Hydrogen reference electrode was used.If 10 ml of 0.2 M Fe*2 was titrated against 0.2 M of Ce*, the E for this reaction upon adding 10.2 ml of Ce4* is:4a. 0.99 Vb. 1.70 VC 1.10 Vd. 1.60 V

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Answered: 22ln an Electrolytic cell with Fe and…

22ln an Electrolytic cell with Fe and Sn electrodes, calculate the E°ce knowing that Fe+ e > Fe*2 E°= 0.771 V and Sn 2e > Sn E°= - 0.14 V. 2 O a. 0.627 V O b. - 0.627 V O c. 0.911 V O d. -0.911 V

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

22ln an Electrolytic cell with Fe and Sn electrodes, calculate the E°ce knowing that
Fe*3+ e => Fe*2 E°= 0.771 V
and Sn2*+ 2e => Sn
E°= - 0.14 V.
O a. 0.627 V
O b. - 0.627 V
O c. 0.911 V
O d. -0.911 V
10Which is incorrect for minimizing the decomposition of Sodium thiosulfate solutions
O a. Adjust the pH (9-10)
O b. Standard solutions of reagents are prepared under sterile conditions
Oc The presence of bactericides, such as chloroform, sodium benzoate
O d. Standard solutions of reagents are prepared in absence of oxygen
24 In the reaction
Ce* + Fe2* è Ce + Fe*
Knowing that Fe + e ==> Fe*2 E= 0.767 V
Ce* +e ==> Ce3 E= 1.70 V
And Hydrogen reference electrode was used.
If 10 ml of 0.2 M Fe*2 was titrated against 0.2 M of Ce*, the E for this reaction upon adding 10.2 ml of Ce4* is:
4
a. 0.99 V
b. 1.70 V
C 1.10 V
d. 1.60 V

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