20 KN20 KNACTIVITY 320 KN10 KN/m10 KN/mABPROBLEM 120 KN/mTTTT10 KN/m+CComputethe10 KN-m10 KN/m10 KN/mEFG10 KN/mreactions atthe fixedşupport ofBeam KL10 KN/mK20 KN/m1.00 1.002.001.501.00 1.00 1.00 1.004.00All dimensions in meters0.50

Answered: Image /qna-images/answer/d5c95292-f7c6-4e6b-850f-f44116fe9f5e.jpg

20 KN 20 KN ACTIVITY 3 20 KN 10 KN/m 10 KN/m A PROBLEM 1 20 KN/m 10 KN/m C Compute the 10 KN-m 10 KN/m 10 KN/m F 10 KN/m reactions at the fixed Şupport of Beam KL 10 KN/m 20 KN/m 1.00 1.00 2.00 1.50 1.00 1.00 1.00 1.00 4.00 All dimensions in meters 0.50

20 KN 20 KN ACTIVITY 3 20 KN 10 KN/m 10 KN/m A PROBLEM 1 20 KN/m 10 KN/m C Compute the 10 KN-m 10 KN/m 10 KN/m F 10 KN/m reactions at the fixed Şupport of Beam KL 10 KN/m 20 KN/m 1.00 1.00 2.00 1.50 1.00 1.00 1.00 1.00 4.00 All dimensions in meters 0.50

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.

Question

20 KN
20 KN
ACTIVITY 3
20 KN
10 KN/m
10 KN/m
A
B
PROBLEM 1
20 KN/m
TTTT
10 KN/m
+
C
Compute
the
10 KN-m
10 KN/m
10 KN/m
E
F
G
10 KN/m
reactions at
the fixed
şupport of
Beam KL
10 KN/m
K
20 KN/m
1.00 1.00
2.00
1.50
1.00 1.00 1.00 1.00
4.00
All dimensions in meters
0.50

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