2.0 atmadiabaticisothermal16.0 L40.0LVA thermodynamic cycle of 1.000 mol of monoatomic perfect gas (Cv,m = 12.47 JK1 mol1) consist of the following 3 stages:STAGE 1:1 to Il ; adiabatic reversible expansion from(T1 =273K, V:= 16.0 L, P1= 2.00 atm) to (T2= ?, P2=1atm, V2= 40.0 L)STAGE 2, Il to Il ;isothermal reversible compression from (T2 =?, V2 = 40L, P2 = 1.00 atm) to (T3 = ?, V3 = 16L, P3=?)STAGE 3: IIII to l; isochoric heating from (T3 =?, V3 = 16 L, P3 = ?) to (T1 = 273K, V = 16 L, P1 = 2 atm)What is the Stage 1 final temperature, T,? Answer in Kelvin in 3 significant figures.Type your answer.What is the change in internal energy (in kJ) in the Stage 1 process? Answer in 3 significant figures.Type your answer.2 pointsCalculate q (in kJ) for the Stage 2 process. Answer in 3 significant figures.Type your answer.pointCalculate q (in kJ) for the stage 3 process. Answer in 3 significat figuresType your answer.What is the overall change in internal energy (in kJ) for the cycle (The sum of the change in internal energy of Stages 1,2 and 3)?Answer in 3 significant figuresType your answer.

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Answered: 2.0 atm adiabatic isothermal 16.0 L…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A closed cylinder contains 1.0 mole of ideal monatomic gas at 300 oC and 4.0 bar.Insulating the cylinder so that there is no heat exchange with the surroundings, the gas isexpanded to 200 oC and 1.0 bar producing 1247 J of work.a) Is this process reversible or irreversible?b) What is the change in enthalpy (∆H) of the gas?c) What is the change in internal energy (∆U) of thegas?
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1. The specific heat capacities (in units of J/g-K) of V, W, and Zn are 0.489, 0.132, and 0.388, respectively. What is the order of the molar heat capacities? Formula weights: V 50.94; W 183.8; Zn 65.4 (c) W>V>Zn (a) V>W>Zn (d) W>Zn>V (b) V>Zn>W (e) Zn>V>W
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(a) Suppose that attractions are the dominant interaction between gas molecules, and the equation of state is p = nRT/V – n2a/V2. Determine the work (W(non-ideal gas)) of reversible, isothermal expansion of such a gas from initial volume V (initial) = 20.0 L to final volume V(final) = 40.0 L if n = 2.00 mol, T = 300 K, and a = 3.621 atm-L2/mol2. Watch your units. (b)Determine the work (W(ideal gas) of reversible, isothermal expansion of an ideal gas from initial volume V (initial) = 20.0 L to final volume V(final) = 40.0 L if n = 2.00 mol and T = 300 K. (c) Show the difference W(non-ideal) – W(ideal). If all your calculations are done correctly, this result shows you the effect of attractive interaction between gas particles on the work done by the system.
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