2. Figure 1(b) shows a BJT based current mirror with a NMOS M3 based beta helper circuit. The current equation of the NMOS is given by: Kn (Vcs - Vrn) (1+ aVps) In = 2 where Kn= 100 uA/V², VTn = 0.5 V and 2 → 0. Other parameters of the circuit are same as the earlier part of the question. (a) Derive the equation of mirror ratio MR = IJIREF. Using this, find Io, VBE1 and VCEI if AEI = 2, AE2 = 2. (b) Derive the equation of mirror ratio MR = I/IREF. Using this, find Io, VBEI and VCEI if AEI = 2, AE2 = 20. (c) Recalculate the values of MR and I, if VA = 50 V for both the cases of AE2 = 2 and 20 while AEI = 2 Vdd ()IREF 1,=Ic2 M3 E2 El V BE ВЕ GND = 0V (b)
2. Figure 1(b) shows a BJT based current mirror with a NMOS M3 based beta helper circuit. The current equation of the NMOS is given by: Kn (Vcs - Vrn) (1+ aVps) In = 2 where Kn= 100 uA/V², VTn = 0.5 V and 2 → 0. Other parameters of the circuit are same as the earlier part of the question. (a) Derive the equation of mirror ratio MR = IJIREF. Using this, find Io, VBE1 and VCEI if AEI = 2, AE2 = 2. (b) Derive the equation of mirror ratio MR = I/IREF. Using this, find Io, VBEI and VCEI if AEI = 2, AE2 = 20. (c) Recalculate the values of MR and I, if VA = 50 V for both the cases of AE2 = 2 and 20 while AEI = 2 Vdd ()IREF 1,=Ic2 M3 E2 El V BE ВЕ GND = 0V (b)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Transcribed Image Text:2. Figure 1(b) shows a BJT based current mirror with a NMOS M3 based beta helper circuit.
The current equation of the NMOS is given by:
Kn
(Vcs - Vrn) (1+ aVps)
In =
2
where Kn= 100 uA/V², VTn = 0.5 V and 2 → 0. Other parameters of the circuit are same as the
earlier part of the question.
(a) Derive the equation of mirror ratio MR = IJIREF. Using this, find Io, VBE1 and VCEI if
AEI = 2, AE2 = 2.
(b) Derive the equation of mirror ratio MR = I/IREF. Using this, find Io, VBEI and VCEI if
AEI = 2, AE2 = 20.
(c) Recalculate the values of MR and I, if VA = 50 V for both the cases of AE2 = 2 and 20
while AEI = 2
Transcribed Image Text:Vdd
()IREF
1,=Ic2
M3
E2
El
V BE
ВЕ
GND = 0V
(b)
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