Consider the graph showing the emf as a function of temperature for the electrochemical cell made of thesolutions of CuSO4 and Pb(NO3)2-180160140120100E. mV40200620640T. Ky=-1,411x + 1059,R²=0,998660680700Given that emf at 660K is 45.6 mV, calculate AH for the system.30°CENG

According to the Gibbs-Helmholtz equation, the temperature coefficient of emf of the cell is -…

Answered: 180 160 140 120 100 80 60 E. mV 40 20 0…

180 160 140 120 100 80 60 E. mV 40 20 0 620 640 T. K y=-1,411x + 1059, R² = 0,998 660 680 700 Given that emf at 660K is 45.6 mV, calculate AH for the system. 30″℃

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Consider the graph showing the emf as a function of temperature for the electrochemical cell made of the
solutions of CuSO4 and Pb(NO3)2-
180
160
140
120
100
E. mV
40
20
0
620
640
T. K
y=-1,411x + 1059,
R²=0,998
660
680
700
Given that emf at 660K is 45.6 mV, calculate AH for the system.
30°C
ENG

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