note: SN is equal to 18, 100 + SN for topload will now be 118kN 3. Factor Method: The frame shown is subjected to lateral loads as shown. Supports S, T, U V, W and Xare rigid supports.Determine the following.c) The moment at the end of each member. 5.0 m5.50 m6.0 m7.0 m5.0 m(1b0+SN) KN1.511.51B1.51144 kN.1.512121DEF1.5121211.51120 kN1.512131JK1.51212.512.512196 KN21213131MNR21313131211.51 cV215.0 m4.50 m4.20 m4.0 m

Assumptions of portal method; 1.The point of contraflexure is at the midpoint of all the members of…

120 kN 96 KN (160+SN) KN 144 KN H 1.51 M 21 ST 1.51 21 D 1.51 21 N 31 T 1.51 1.51 21 21 B 1.51 E 21 2.51 O 31 U 1.51 21 21 31 K P V 21 2.51 31 21 31 31 O W 1.51 21 21 R X 4.0 m 4.20 m 4.50 m 5.0 m 1.51 c

120 kN 96 KN (160+SN) KN 144 KN H 1.51 M 21 ST 1.51 21 D 1.51 21 N 31 T 1.51 1.51 21 21 B 1.51 E 21 2.51 O 31 U 1.51 21 21 31 K P V 21 2.51 31 21 31 31 O W 1.51 21 21 R X 4.0 m 4.20 m 4.50 m 5.0 m 1.51 c

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

note: SN is equal to 18, 100 + SN for topload will now be 118kN

3. Factor Method: The frame shown is subjected to lateral loads as shown. Supports S, T, U V, W and X
are rigid supports.
Determine the following.
c) The moment at the end of each member.

5.0 m
5.50 m
6.0 m
7.0 m
5.0 m
(1b0+SN) KN
1.51
1.51
B
1.51
144 kN.
1.51
21
21
D
E
F
1.51
21
21
1.51
120 kN
1.51
21
31
J
K
1.51
21
2.51
2.51
21
96 KN
21
21
31
31
M
N
R
21
31
31
31
21
1.51 c
V
21
5.0 m
4.50 m
4.20 m
4.0 m

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Step 1: Assumptions of portal method.

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Step 2: indicating the nodes in the frame.

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Step 3: Column shear.

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Step 4: Column Moment.

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