10 100 80 IR Spectrum quid fim) 4000 72 % of base peak 3000 78 80 40 13C NMR Spectrum (100 MHz. CDCI, solution) DEPT CH, CH, CH proton decoupled 200 ¹H NMR Spectrum (400 MHz. CDCI, solution) expansion 7.0 68 ppm 9 8 2000 M 108 120 160 1600 v (cm') 7 160 www 1200 800 Mass Spectrum C7HgO 280 solvent 80 m/e 6 200 120 240 5 4 Problem 22 UV Spectrum -max 269 nm (log10 32) solvent methanol 3 40 2 0 1 8 (ppm) TMS 0 8 (ppm)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the IR and HNMRAndCNMR and mass
10
100
80
60
IR Spectrum
(quid film)
4000
72
L
f base peak
wwwwwww
p
3000
20
40
13C NMR Spectrum
(100 MHz, CDCI, solution)
DEPT CH, CH₂ CH
proton decoupled
200
¹H NMR Spectrum
(400 MHz. CDCI, solution)
expansion
7.0
L
9
6.8
78
L
8
80
ppm
93
L
2000
M** 108
120
160
L
7
V (cm¹)
160
1600
m/e
6
200
120
1200
800
Mass Spectrum
C7H8O
280
solvent
80
4
240
5
Problem 22
UV Spectrum
-max 269 nm (log₁0 32)
....
solvent methanol
3
40
2
0
1
8 (ppm)
TMS
0
8 (ppm)
Transcribed Image Text:10 100 80 60 IR Spectrum (quid film) 4000 72 L f base peak wwwwwww p 3000 20 40 13C NMR Spectrum (100 MHz, CDCI, solution) DEPT CH, CH₂ CH proton decoupled 200 ¹H NMR Spectrum (400 MHz. CDCI, solution) expansion 7.0 L 9 6.8 78 L 8 80 ppm 93 L 2000 M** 108 120 160 L 7 V (cm¹) 160 1600 m/e 6 200 120 1200 800 Mass Spectrum C7H8O 280 solvent 80 4 240 5 Problem 22 UV Spectrum -max 269 nm (log₁0 32) .... solvent methanol 3 40 2 0 1 8 (ppm) TMS 0 8 (ppm)
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