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1. Density Calculation Please compute the density of Berylium (Be). Crystal structure = HCP (Hexagonal Close-Packed) Other data please find in your text book or internet. Compare with the real density of Berylium. Formula nA VNA n= number of atom A = Atomic mass V = Volume unit cell Na = Avogardo number Your Answer: Vc = Bottom area x Height Bottom area hexagonal = |(3V3 s)/ 2 c/a = browse in internet Vatom =4/3 xnxr NA= 6.022 x 10atoms/mol

1. Density Calculation Please compute the density of Berylium (Be). Crystal structure = HCP (Hexagonal Close-Packed) Other data please find in your text book or internet. Compare with the real density of Berylium. Formula nA VNA n= number of atom A = Atomic mass V = Volume unit cell Na = Avogardo number Your Answer: Vc = Bottom area x Height Bottom area hexagonal = |(3V3 s)/ 2 c/a = browse in internet Vatom =4/3 xnxr NA= 6.022 x 10atoms/mol

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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1. Density Calculation Please compute the density of Berylium (Be). Crystal structure = HCP (Hexagonal Close-Packed) Other data please find in your text book or internet. Compare with the real density of Berylium. Formula nA VNA n= number of atom A = Atomic mass v. = Volume unit cell Na = Avogardo number Your Answer: Vc = Bottom area x Height Bottom area hexagonal (3V3 s')/ 2 c/a = browse in internet Vatom =4/3 x nxr Na= 6.022 x 10 atoms/mol
Transcribed Image Text:1. Density Calculation Please compute the density of Berylium (Be). Crystal structure = HCP (Hexagonal Close-Packed) Other data please find in your text book or internet. Compare with the real density of Berylium. Formula nA VNA n= number of atom A = Atomic mass v. = Volume unit cell Na = Avogardo number Your Answer: Vc = Bottom area x Height Bottom area hexagonal (3V3 s')/ 2 c/a = browse in internet Vatom =4/3 x nxr Na= 6.022 x 10 atoms/mol
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