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A: Given Data : Sample Size, n = 55 Significance level, α =1- 0.99 = 0.01
We have to find c such that
P(X < θ < cX) = 1 - α
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- (a) A 100(1 − ?)% confidence interval for the mean ? of a normal population when the value of ? is known is given by x − z?/2 · ? n , x + z?/2 · ? n . Under the same conditions as those leading to the interval, P (X − ?) ? √n < 1.645 = 0.95. Use this to derive a one-sided interval for ? that has infinite width and provides a lower confidence bound on ?. x − 1.645 ? n , ∞ ∞, x + 1.645 ? n ∞, x − 1.645 ? n x + 1.645 ? n , ∞ x − 1.645 ? n , ∞ What is this interval for the true average porosity of a certain seam of coal samples that is normally distributed with true standard deviation 0.79 if the average porosity for 20 specimens from the seam was 4.85? (If you need to use or –, enter INFINITY or –INFINITY,…Over the years, the mean customer satisfaction rating at a local restaurant has been 79. The restaurant was recently remodeled, and now the management claims the mean customer rating, u, is not equal to 79. In a sample of 51 customers chosen at random, the mean customer rating is 81.2. Assume that the population standard deviation of customer ratings is 7.5. Is there enough evidence to support the claim that the mean customer rating is different from 79? Perform a hypothesis test, using the 0.10 level of significance. (a) State the null hypothesis H, and the alternative hypothesis H,. Ho- C=D (b) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. • The value of the test statistic is given byUrgent solution required round off to 2dp
- X Your answer is incorrect. (b) Find a 90% confidence interval for the mean increase in production of interferon gamma after drinking tea for one week. Round your answers to one decimal place. The 90% confidence interval is i to i Save for Later Attempts: 1 of 4 used Submit swer e here to searchi need the answer quicklyThe critical value of F for an alpha level of 0.05 and 2 and 12 degrees of freedom is 3.88. if the observed F value of 6.67 is greater than 3.88. what happens to the null hypothesis and explain your position?
- #11 A sample of 2,018 American adults was asked how they viewed China, with 13% of respondents calling the country "unfriendly" and 9% of respondents indicating the country was "an enemy". Construct a 95% confidence interval of the proportion of American adults who viewed China as either "unfriendly" or "an enemy." Multiple Choice [0.2049, 0.2351] [0.1916, 0.2484] [0.2111, 0.2289] [0.2019, 0.2381]6You wish to test the following claim (Ha) at a significance level of α=0.002α=0.002. Ho:p1=p2 Ha:p1≠p2 You obtain 480 successes in a sample of size n1=647 from the first population. You obtain 562 successes in a sample of size n2=737 from the second population. For this test, you should NOT use the continuity correction, and you should use the normal distribution as an approximation for the binomial distribution. What is the standardized test statistic for this sample? (Report answer accurate to three decimal places.)
- A Express the confidence interval 0.444 < p <0.888 in the form p±E. p±E= +C H- Construct the 99% confidence interval for the difference μ₁ −μ₂ when x₁=476.88, x₂=318.32, s₁=42.11, s₂=26.80, n₁=19, and n₂=22. Use tables to find the critical value and round the answers to at least two decimal places. A 99% confidence interval for the difference in the population means isThe group of students had a test on Statistics. The following student’s blood pressure results are given in the table before and after the test: Student 1 2 3 4 5 6 7 8 before 70 74 73 80 74 85 81 75 after 72 78 75 79 84 88 82 78 а) Find 95% confidence interval for the μd - difference of the student’s blood pressure results before and after the test, b) Do the data support that the blood pressure is changed at the α=0.05? The difference is believed to be approximately normally distributed.