. Kari attempts to solve the exponential equation 3 (2")= algebraically and then checks the solution graphically. Kari's two methods arrive at different solutions, as shown below. 3(2-) = // 3(2-) = 2² = ² = 2³ x=3 Where did Kari make an error and what is the correct solution? Select all that apply. -2 The error is that Kari cannot multiply both sides of the equation by The correct solution is z -3. The error is that = 2³, not 2³. The error is that the line y = is graphed too low. The error is that the curve y = 3 (2") is graphed too high. The error is that= -2³, not 2³. = 3. The correct solution is a =
. Kari attempts to solve the exponential equation 3 (2")= algebraically and then checks the solution graphically. Kari's two methods arrive at different solutions, as shown below. 3(2-) = // 3(2-) = 2² = ² = 2³ x=3 Where did Kari make an error and what is the correct solution? Select all that apply. -2 The error is that Kari cannot multiply both sides of the equation by The correct solution is z -3. The error is that = 2³, not 2³. The error is that the line y = is graphed too low. The error is that the curve y = 3 (2") is graphed too high. The error is that= -2³, not 2³. = 3. The correct solution is a =
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question

Transcribed Image Text:Kari attempts to solve the exponential equation 3 (2)
solution graphically. Kari's two methods arrive at different solutions, as shown below.
3. (2x) = ²/
3(2-) =
2x = = = 2³
x = 3
A
-3
algebraically and then checks the
Where did Kari make an error and what is the correct solution? Select all that apply.
The correct solution is a = 3.
The error is that Kari cannot multiply both sides of the equation by
The correct solution is z = -3.
The error is that 23, not 23.
The error is that the line y
is graphed too low.
The error is that the curve y=3-(2") is graphed too high.
The error is that +
-2³, not 2³.
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