M6 Exam
pdf
keyboard_arrow_up
School
Portage Learning *
*We aren’t endorsed by this school
Course
110
Subject
Statistics
Date
Jan 9, 2024
Type
Pages
13
Uploaded by ChefOwl3912
M6:
Exam
-
Requires
Respondus
LockDown
Browser
+
Webcam
Due
No
due
date
Points
50
Questions
5
Time
Limit
90
Minutes
Requires
Respondus
LockDown
Browser
Instructions
You
may
only
have
the
following
items
when
taking
an
exam:
computer,
1-2
pieces
of
blank
scratch
paper,
a
pen/pencil,
and
a
calculator.
You
may
ONLY
use
the
equation
sheets
that
are
provided
WITHIN
the
exam.
The
use
of
printed
versions
will
be
considered
a
violation
of
the
Academic
Integrity
Policy.
Attempt
History
Attempt
Time
Score
LATEST
Attempt
1
86
minutes
45
out
of
50
Score
for
this
quiz:
45
out
of
50
Submitted
Aug
28
at
6:09pm
This
attempt
took
86
minutes.
Question
1
10
/10
pts
You
may
find
the
following
files
helpful
throughout
the
exam:
Statistics_Equation_Sheet
=
table.pdf)
A
new
drug
is
introduced
that
is
supposed
to
reduce
fevers.
Tests
are
done
with
the
drug.
The
drug
is
given
to
60
people
who
have
fevers.
It
is
found
that
the
mean
time
that
it
takes
for
the
fever
to
get
back
to
normal
for
this
test
group
is
350
minutes
with
a
standard
deviation
of
90
minutes.
Find
the
80%
confidence
interval
for
the
mean
time
that
the
drug
will
take
to
reduce
all
fevers
for
all
people.
Answer
the
following
questions:
1.
Multiple
choice:
Which
equation
would
you
use
to
solve
this
problem?
S
S
B
¥—fl——=
<
S
X+t—
va
F
Vn
C
-
s
N—n<
<
7+
s
|[N—n
X
—
Z=——
X+
2=
JndN=1
>
F
%
JN=1
1_
D
P+
z
p(1-p)
n
2.
List
the
values
you
would
insert
into
that
equation.
3.
State
the
final
answer
to
the
problem
Your
Answer:
1.A
2.
n=60,
s=90,
|z
=
350
3.
Table
shows
z=1.28
~
{98
90
90
350
—
12878
<
1
<350
+1.28-%
335.13
<
p
<
364.87
The
drug
will
ultimately
sold
to
a
very
large
number
of
people.
So,
we
may
assume
a
very
large
population.
Since
the
sample
size
is
greater
than
30,
we
should
use
Case
1:
Very
large
population
and
very
large
sample
size.
We
are
given
the
sample
mean
and
sample
standard
deviation.
So,
we
have
n=60
x
=350
s=90
We
will
use
these
values
in
the
equation:
_
s
_
s
A
X—Z2—
<<
x+Z2—
Vn
Vn
For
a
80%
confidence
level,
we
look
at
table
6.1
and
find
that
z
=
1.28.
When
we
substitute
these
values
into
our
equation, we
get:
90
90
350
-
128
—
<
u<
350+
1.28
—
V60
V60
When
we
do
the
arithmetic
on
the
right
and
left
hand
side,
we
get:
335.13
<
<
364.87.
Question
2
10/
10
pts
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
You
may
find
the
following
files
helpful
throughout
the
exam:
Statistics_Equation_Sheet
=
(https://previous.nursingabc.com/upload/images/Help_file
picture/Statistics
Standard
Normal
Table
&
(https://previous.nursingabc.com/upload/images/Help_file
picture/standardn
T
Table
5
(https://previous.nursingabc.com/upload/images/Help_file_picture/t-
table.pdf)
A
certain
school
has
275
male
students.
The
school
nurse
would
like
to
know
how
many
calories
the
male
students
consume
per
day.
So,
she
samples
40
male
students
and
finds
that
the
mean
calorie
consumption
of
the
40
is
2670
calories
per
day
with
a
standard
deviation
of
330
calories
per
day.
Find
the
95
%
confidence
interval
for
mean
calorie
intake
of
all
the
male
students
in
the
school.
Answer
the
following
questions:
1.
Multiple
choice:
Which
equation
would
you
use
to
solve
this
problem?
s
B
S
A
F—RreiCig&
PR
vn
vn
B
X
ts
<
'-I-ts
X
—t=—=
<
X
—
n
K
Vn
s
N-—-n
S
N~—-n
C.
¥—-z—
<
u<
¥x+z—
Vi
N
-
nJN-1
1_
D
l,j:zp(
p)
2.
List
the
values
you
would
insert
into
that
equation.
3.
State
the
final
answer
to
the
problem
Your
Answer:
1.C
2.
N=275,
n=40,
s=330,
|7
=
2670
3.
For
95%
confidence
z=1.960
|267O
—
1.960-2%
\/
227755
410
<
<
2670
+
1.960-35C
\/
227755__410
12575.3
<
pu
<
2764.7|
The
population
is
finite.
So,
we
should
use
Case
3:
Finite
population.
Use:
In
the
statement
of
the
problem,
we
are
given:
N=275
n=40
x
=2670
s=330
For
a
95%
confidence
level,
table
6.1
gives
z=1.96
e
IR
ol
i
R
2670
+
1.96
o
i
P
a0
J275-1
O
F
P
Va0
J
2751
2575.29
<
u<
2764.71
Question
3
9/10
pts
You
may
find
the
following
files
helpful
throughout
the
exam:
Statistics_Equation_Sheet
=
table.pdf)
In
a
large
city,
the
city
supervisor
wants
to
find
the
average
number
of
aluminum
cans
that
each
family
recycles
per
month.
So,
she
surveys
21
families
and
finds
that
these
21
families
recycle
an
average
of
160
cans
per
month
with
a
standard
deviation
of
45
cans
per
month.
Find
the
90
%
confidence
interval
for
the
mean number
of
cans
that
all
of
the
families
in
the
city
recycle
per
month.
Answer
the
following
questions:
1.
Multiple
choice:
Which
equation
would
you
use
to
solve
this
problem?
S
S
A
BB
PR
vn
Vn
P
o
o
e
B
¥x—t—
<
X
—
va
F
Vn
C
-
s
N—n<
<
7+
s
|[N—n
X
—
Z
=
X+t
Z=—
JndN=1
>
F
%
JN=1
1-—
D
l,j:zp(
p)
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
2.
List
the
values
you
would
insert
into
that
equation.
3.
State
the
final
answer
to
the
problem
Your
Answer:
1.B
2.
|z
=
160},
s=160,
n=21
3.
45
160
+
1'725fi
176.94
<
p
<
143.06
We
have
a
very
large
population
but
the
sample
size
is
small.
We
should
use
Case
2:
Very
large
population
and
small
sample
size.
Use
S
S
B
x+t—
Vn
When
we
look
at
the
student’s
t
chart
for
90%
confidence
(the
90%
is
found
along
the
bottom
row
of
the
chart)
and
df=21-
1=20
(the 20
is
found
in
the
leftmost
column)
we
find
that
t=1.725.
So,
160
+
1.725
2
SR
160116.94
143.06<u<176.94
Careful.
State
the
Cl
as
a
lower
limit
to
an
upper
limit.
Question
4
8
/10
pts
You
may
find
the
following
files
helpful
throughout
the
exam:
Statistics_Equation_Sheet
&
(https://iprevious.nursingabc.com/upload/images/Help_file
picture/Statistics
Standard
Normal
Table
&
(https://previous.nursingabc.com/upload/images/Help_file_
picture/standardn
T
Table
(https://iprevious.nursingabc.com/upload/images/Help_file
picture/t-
table.pdf)
A
doctor
has
a
large
number
of
patients
and
would
like
to
know
if
his
patients
prefer
to
fill
in
forms
electronically
or
prefer
to
hand
write
their
forms.
So,
he
surveys
110
patients
and
finds
that
52
prefer
electronic
forms
while
58
prefer
hand
written
forms.
Find
the
90%
confidence
limit
for
the
proportion
of
all
patients
that
prefer
the
electronic
forms.
Answer
the
following
questions:
1.
Multiple
choice:
Which
equation
would
you
use
to
solve
this
problem?
s
B
s
A
F—RriCig&
PR
vn
Vn
B
o
£+
t—
"
)
Cy—]
<X
-_—
va
F
Vn
C
-
s
N—n<
<
7+
s
|[N—n
X
—
Z=——
X+
2=
JndN=1
>
F
%
JN=1
1_
D
l,j:zp(
p)
2.
List
the
values
you
would
insert
into
that
equation.
3.
State
the
final
answer
to
the
problem
Your
Answer:
1.D
2.
N=110,
sample
proportion
x/n=52/110=.473,
z
multiplier
.05/2=1.959
3.
52/110=.483
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
483
+
1645,/
2049
483
+
078
405
to
.561
We
have
an
infinite
population
we
will
use
Case
1:
D.
Pizp_(t_p_)
,‘
n
The
proportion
that
prefer
the
electronic
forms
is
52/110
=.47
so
we
set
P=.47.
As
we
mentioned
previously,
we
estimate
p
by
P.
So,
p=.47.
A
total
of
110
patients
were
surveyed,
so
n=110.
Based
on
a
confidence
limit
of
90
%,
we
find
in
table
6.1
that
z=1.645.
Now,
we
can
substitute
all
of
these
values
into
our
equation:
A47(1
-
47)
47
+
1.645]
110
47
£
.078
So, the
90%
confidence
limit
is:
.39
to
.548
Question
5
8/10
pts
You
may
find
the
following
files
helpful
throughout
the
exam:
Statistics_Equation_Sheet
=
T
Table
&>
table.pdf)
A
shipment
of
350
new
blood
pressure
monitors
have
arrived.
Tests
are
done
on
60
of
the
new
monitors
and
it
is
found
that
8
of
the
60
give
incorrect
blood
pressure
readings.
Find
the
80%
confidence
interval
for
the
proportion
of
all
the
monitors
that
give
incorrect
readings.
Answer
the
following
questions:
1.
Multiple
choice:
Which
equation
would
you
use
to
solve
this
problem?
S
S
A
F—RreiCig&
PR
vn
Vn
B.
¥
o
e
I
X
o
—]
<
X
e
va
F
Vn
C
-
s
N—n<
<
7+
s
|[N—n
X
—
Z
=
X+t
Z=—
JndN=1
>
F
%
JN=1
1-—
D
l,j:zp(
p)
2.
List
the
values
you
would
insert
into
that
equation.
3.
State
the
final
answer
to
the
problem
Your
Answer:
1.
E
2.
N=350,
n=60,
x=8
3.
8/60=.133
153+
1282,
[T
[
1.33
+.01)
1.32
to
1.34
We
have
a
finite
population,
so
we
will
use
Case
2:
The
proportion
of
the
sample
that
are
defective
is
8/60
=
.1333
so
we
set
P=.1333.
As
we
mentioned
previously,
we
estimate
p
by
P.
So,
p=.1333.
A
total
of
60
monitors
were
tested,
so
n=60.
Based
on
a
confidence
limit
of
80
%,
we
find
in
table
6.1
that
z=1.28.
The
total
number
of
monitors
is
350,
so
set
N=350.
Now,
we
can
substitute
all
of
these
values
into
our
equation:
.1333(1
—.1333) jzso
—
60
.1333
+
1.28J
50
350
—
1
13331
.0512
So
the
proportion
of
the
total
that
are
defective
is
between
.0821
and
.1845.
Careful
with
the
decimal
value
of
p.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Quiz
Score:
45
out
of
50
Recommended textbooks for you
Algebra: Structure And Method, Book 1
Algebra
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:McDougal Littell
Recommended textbooks for you
- Algebra: Structure And Method, Book 1AlgebraISBN:9780395977224Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. ColePublisher:McDougal Littell
Algebra: Structure And Method, Book 1
Algebra
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:McDougal Littell