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Utah State University *

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Statistics

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Apr 3, 2024

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Inferential Statistics: Inferential statistics use laws of probability to make inferences about a population based on information gleaned from a sample . Such statistics are particularly useful given the unlikely occurrence that a researcher has access to an entire population. Experiment: the process of making an observation. Will result in only one basic outcome. Sample Space: is the collection of all its sample points in an experiment. Sample Point: The only result of an experiment. Flipping a coin multiple times, .5 for heads or tails. Must be between 0 and 1. All the probabilities added together should equal 1. Probability: For example, if a fair coin is tossed, we might reason that both the sample points, observe a head and observe a tail, have the same chance of occurring. Thus, we might state that “the probability of observing a head is 50%” or “the odds of seeing a head are 50:50.” Event: a specific collection of sample points (s: {1,2,3,4,5,6}) Combinations Rule: When a sample of n elements needs to be drawn from a set of N elements. NO REPLACEMENT. Selecting 4 books from a stack of 10. Quiz: An urn is filled with 6 marbles: 3 red, 2 blue, and 1 black. Suppose we draw one marble at random from the urn. Use this information to answer the following questions. - An example of a sample point for this experiment is: blue - The sample space for this experiment is: {red, blue, black} - The probability I draw a red marble is: 1/2 - If A represents the event of drawing either a red or blue marble, the complement of A is: drawing a black marble - Suppose I draw 3 marbles from the urn. How many different combinations of marbles could I draw: 20 - Suppose I now add 3 green marbles to the urn. The probability of drawing a green marble is: 1/3 - With the green marbles added, the probability I draw either a red or blue marble is: 5/9 - The probability of the complement of the event described in the previous question is: 4/9 Unions: if either A or B or both occur on a single performance of the experiment. A B = P(A) + P(B) – P(A B) Intersections : if both A and B occur on a single performance of the experiment. A B = P(AIB)P(B) Additive Rule of event Union: The probability of the union of events A and B is the sum of the probabilities of events A and B minus the probability of the intersection of events A and B Mutually exclusive: Events A and B have no sample points in common. P(A B) = 0 Prob of Union of two mutually exclusive events: P(A B) = P(A) + P(B) Quiz: Use the twister board to answer the following questions: - The sample space for the color the spined could land on is: {green, red, yellow, blue} - The probability the spinner will land on a red section is: 1/4 - The probability the spinner will land in the left hand section is: 1/4 - The probability the spinner will land in the right foot section and on a yellow section is: 1/16 - The probability the spinner will land on either a red section or in the left hand section is: 7/16 - The compliment of the probability described in the previous question is: the probability the spinner will land in a section that is not red and not left handed - The sinner landing in the left food section and the spinner landing in the right foot section are an example of: mutually exclusive events Quiz: A couple plans to have three children. Use this information to answer the following questions. - Let B represent a boy and G represent a girl. The sample space for the genders of the three children is: {BBB, BBG, BGB, GBB, BGG, GBG, GGB, GGG} - If a girl or boy is equally likely for each birth, the probability associated with each of the outcomes in the sample space is: 1/8 - The probability that the couple has at least one child of each gender is: 3/4 - In words, the complement of the event described in the previous question is: the couple has all one gender (all boys or all girls) - The probability of the complement of the couple having at least one child of each gender is: 1/4
Conditional Probability: Refers to the change that some outcome occurs given that another event has also occurred. P(AIB), where the probability of B depends on that of A happening. Multiplicative Rule: The probability of an intersection of two events. Independence regarding two events: If events A and B are independent, the probability of the intersection of A and B equals the product of the probabilities of A and B; that is, P(A B) = P(A)P(B) . The converse is also true. Dependent if it does not equal the other. Random sampling = independent: Each member of the population has an equal, independent, and known chance of being selected. Bayes’ Rule: Can be applied when an observed event A occurs with any one of several mutually exclusive and exhaustive events, B1, B2,…,Bk. Quiz: For two events A and B, let P(A) = .3, P(B) =.5, and P(A B) = .2. Use this information to answer the following questions. - P(AIB) is: .40 - P(BIA) is: .67 - A and B are independent: false - P(A B) is: .6 Quiz: In a recent survey of ethnicity and church attendance within the U.S., the percentage who report attending weekly was 29.7% among whites, 40.7% among blacks, 29.8% among Hispanics, and 26.1% among all other races combined. Given that 72% of the U.S. population identifies themselves as white, 13% as black, 6% as Hispanic, and 9% as another race, answer the following questions. - Let H represent Hispanics and A represent attending church weekly. What is P(AIH): .298 - What proportion of the U.S. population is black and attends church weekly: .407 x .13 = .052 - What percentage of Americans attend church weekly: ( 29.7% × 72% ) + ( 40.7% × 13% ) + ( 29.8% × 6% ) + ( 26.1% × 9% ) = 30.8% - Given an individual attends church weekly, what is the probability that person is black: P(Black I Church Attendance) = .169 - To determine if race and church attendance are independent, one could show: P(HIA) = P(H) Quiz: Hypertension is a condition indicated by elevated blood pressure, and is associated with generally poor cardiovascular health. According to researchers, 24% of white American adults (i.e., men and women over the age of 18) are hypertensive, while this is true for 32% of blacks, 21% of Hispanics, and 17% of all other racial groups combined. If 75% of the adult population in the U.S. is white, 12% is black, 6% is Hispanic, and 7% can be classified as belonging to another racial group, then answer the following questions: - Let W represent white American adults and H represent hypertensive adults. What is P(HIW): .24 - What is the probability that you randomly sample a non-hypertensive adult white individual from the U.S. population: 100 – 24 = 76, 76 * 74 = 57% - The proportion of all American adults that is hypertensive is: ( 24% × 75% ) + ( 32% × 12% ) + ( 21% × 6% ) + ( 17% × 7% ) = .243 - Given that a randomly sampled American adult is hypertensive, what is the probability that (s)he is black: P(Black I Hypertensive) = .158 - Race and hypertension are dependent: true
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