Lab 1
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University of Kentucky *
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Course
211
Subject
Statistics
Date
Apr 3, 2024
Type
xlsx
Pages
1
Uploaded by DoctorIron13961
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Understanding the color code for PHY 2XX
PI Name:
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Raw Data Errors in values?
Formula that needs to be entered
Open Response area
DA Name:
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Researcher Name:
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Task 1
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Trial 1 (s) Trial 2 (s) …
Best Data for a single swing
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PI 1.44
1.4
1.29
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DA
1.2
1.41
1.21
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Researcher
1.31
1.45
1.1
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1.42 +/- 0.03
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Task 2
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Data Run 1
Data Run 2
Data Run 3
Data Run 4
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Time (s)
Period (s)
Time (s)
Period (s)
Time (s)
Period (s)
Time (s)
Period (s)
~
0
1.51631
0
1.52729
0
1.52783
0
1.5216
~
0.116364
1.51735
0.04845
1.52796
0.00552
1.52791
0.00865
1.52169
~
0.764655
1.51656
0.76666
1.52736
0.76163
1.52724
0.75935
1.52068
~
0.880384
1.51804
0.81533
1.52804
0.76723
1.52726
0.76802
1.51201
~
1.516309
1.51699
1.52729
1.52817
1.52783
1.52705
1.5216
0.76723
~
1.633717
1.51772
1.57641
1.52884
1.53343
1.52713
1.53034
1.51059
~
2.281219
1.51664
2.29402
1.52705
2.28887
1.5272
2.28003
0.76977
~
2.398425
1.5182
2.34337
1.52771
2.29449
1.52725
2.28003
1.52067
~
3.0333
1.5165
3.05546
1.52684
3.05488
1.52696
2.28883
1.52081
~
3.151437
1.51784
3.10525
1.52746
3.06056
1.527
3.04093
1.52073
~
3.79786
1.51692
3.82107
1.52738
3.81607
1.52672
3.0498
1.52077
~
3.916623
1.51813
3.87108
1.52806
3.82174
1.52682
3.8007
1.51949
~
4.549801
4.5823
4.58184
3.80964
~
4.669273
4.63271
4.58756
4.56166
~
5.314778
5.34845
5.34279
4.57057
~
5.434755
5.39914
5.34856
5.32019
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DA- What is the connection between your measurements between task 1 and task 2. What is the period of the pendulum? (Your answer should include both text and a graph of your data.)
The data in task 1 was recorded as a control group. Therefore, all members of the group each timed one period of the pendulum. The times recorded averaged 1.42 seconds. I compared these times to Data Run 1 from task 2. The average for this data run for the period was 1.52 seconds. These results indicate that when timed with a stopwatch the best time recorded had a period that was a tenth of a second slower than when recorded with a photogate system. The average time of the pendulum changed less than a tenth of a second between data trials 1, 2, &3 when compared to Data Run 1. All of the average period times from Task 2 were within 0.12 seconds compared to the times from Task 1. Group
- Evaluate your data so far:
Changes made from trial 1
Changes made from trial 1,2
Changes made from trial 1,2,3
RELEASING THE PENDULUM AT A LARGER ANGLE MOVING PHOTOGATE LOWER ON ROD RELEASING AT A SMALLER ANGLE Researcher
- What is the Random Uncertainty of your photogate system? What adjustments did you make to the experimental setup or procedure to reduce this uncertainty?
According to the Lab Manual, Random Uncertainty is described as the measure of precison in given data. In this experiment, our Random Uncertanity is 0.0007 seconds. In efforts to decrease the amount of random uncertanity, we made changes to each data run. First, we released the Pendulum at a larger angle. For the third data run, we chose to move the photo gate lower on the rod. Lastly, in data run four, we released the Pendulum at a smaller angle. Our highest random uncerntanity was on data run four with it being 0.0009 seconds. Data run three was the smallest random uncertanity at 0.0004 seconds. Finally, data run two was 0.0006 seconds.
PI
-
Compare your results for two different Task 2 data runs by building a second graph. Is there a “systematic shift” between these two data sets? Can you estimate the size of this shift? Could this be accounted for by the Random uncertainty of your system?
There is a systematic shift between data run one and two but there is so way to estimate the shift. Since there is no way to estimate the systematic shift the random uncertainty can be accounted for because data run two is larger because of the large angle it was released at. Group-
The data in the “Period of Pendulum” graph in the manual has a weird pattern in it. The 1
st
, 5
th
, 9
th
, and 13
th
points are low while the 4
th
, 8
th
, and 12
th
points are high. If you are getting a similar pattern where is it coming from? If no similar pattern appears then you don’t need to worry about this question.
Based on the data collected from Task 2, some Data Run's followed this pattern while other's did not. One example of a Data Run that perfectly follows the pattern described is Data Run 1. Points 1, 5, & 9 were all lower than points 4, 8, and 12. Data Run 2 was similar although point 5 was higher than point 8. Data Run's 3 and 4 did not follow the pattern. In both of these trials both points 1 and 9 were larger than points 4 and 12. This pattern is due to the accuracy vs. precision being greater or lesser between different trials. 0
2
4
6
8
10
12
14
1.51
1.512
1.514
1.516
1.518
1.52
1.522
1.524
1.526
1.528
1.53
Period of Pendulum - Data Run 1 & 2
Swing Number
Period (s)
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Related Questions
Build the 2X2 table (refer to image)
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on 19 students who took the course last semester follow
# of observation(s) n = 19
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mg
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Business Statistics 1 || Spring21
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On average, you receive 2.6 pieces of junk mail a day. Assume that the number of pieces of junk mail you receive each
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了
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R
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* Question Completion Status:
QUESTION 1
The following histogram represents the number of body piercings for students in a statistics class.
40
0 2
4.
9
Number of Piercings
8
a. Is this graph symmetric or skewed?
b. For this graph, is mean or median the best choice for the measure of center?
c. For this graph, is standard deviation or IQR the best choice for the measure of variation?
d. For this graph, the mean expected to be
(higher than, lower than, or about the same as?) the median.
QUESTION 2
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3:49 PM Sat Jan 30
MAT150 Online Assignment #1.docx
Assignment #1 – How to use Calculator
1. If range is 60, number of class is 6, what is the class width? (Round up to next
whole number)
class width ===
2. The data set is 2,4,5,7,10,15, what is sum Ex and the mean (Average)? (Round to
the nearest tenth).
Ex = 2+4+5+7+10+15 =
(n is how many numbers there are)
3. If IQR is 0.69, find Usual Min and Usual Max?
Usual Min = 0.68 – 1.5*IQR =
Usual Max = 1.22 + 1.5*IQR =
4. Fill out the table below:
H= 77.67
58 58 – 77.67 = -19.67 (-19.67)² = 386.9089
LL
5. Fill out the table below:
x P(x) xP(x) x² x´p(x)
00.10
10.30
20.60
6. If , what is
7. If µ=5.5, o=0,1, n=16, what is a µ̟ and o̟?
= 11 = *r.
==0
8. n= 150, o = 6,2, = 1 – 0.99 = 0.01, Z,= Z,005
= 2.575
SO0'0=1 pul
Find 2.2 + E =.
Find 2.2 – E =
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Data: https://mcs.utm.utoronto.ca/~nosedal/data/cfcs.txt
CFC 2 1 1 2 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 2 1 1 1 2 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 1 2 1 2 2 2 2 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 1 2 1 1 1 1 1 2 2 1 1 1 1 1 1 1 2 1 1 1 2 1 1 2 1 1 1 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 2 1 1 1 2 1 1 1 2 2 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 2 1 2 2 1 1 1 1 1 2 1 2 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 2 1 1 2 1 1 1 1 1 1 2 2 2 2 2 1 1 2 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1…
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[Statistics] How do you solve this?
Data: https://mcs.utm.utoronto.ca/~nosedal/data/cfcs.txt
CFC 2 1 1 2 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 2 1 1 1 2 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 1 2 1 2 2 2 2 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 1 2 1 1 1 1 1 2 2 1 1 1 1 1 1 1 2 1 1 1 2 1 1 2 1 1 1 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 2 1 1 1 2 1 1 1 2 2 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 2 1 2 2 1 1 1 1 1 2 1 2 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 2 1 1 2 1 1 1 1 1 1 2 2 2 2 2 1 1 2 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1…
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[Statistics] How do you solve this?
Data: https://mcs.utm.utoronto.ca/~nosedal/data/cfcs.txt
CFC 2 1 1 2 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 2 1 1 1 2 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 1 2 1 2 2 2 2 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 1 2 1 1 1 1 1 2 2 1 1 1 1 1 1 1 2 1 1 1 2 1 1 2 1 1 1 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 2 1 1 1 2 1 1 1 2 2 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 2 1 2 2 1 1 1 1 1 2 1 2 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 2 1 1 2 1 1 1 1 1 1 2 2 2 2 2 1 1 2 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1…
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[Statistics] How do you solve this?
Data: https://mcs.utm.utoronto.ca/~nosedal/data/cfcs.txt
CFC 2 1 1 2 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 2 1 1 1 2 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 1 2 1 2 2 2 2 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 1 2 1 1 1 1 1 2 2 1 1 1 1 1 1 1 2 1 1 1 2 1 1 2 1 1 1 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 2 1 1 1 2 1 1 1 2 2 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 2 1 2 2 1 1 1 1 1 2 1 2 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 2 1 1 2 1 1 1 1 1 1 2 2 2 2 2 1 1 2 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1…
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What is the percentage we're at the $40 million or more range?
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Calculated the population attributable risk (refer to image)
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The x²y5 term in the expansion will be
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(14) Binomial Theorem Exp x
Suppose the binomial expansion of (5x + 2y)" includes the term 175000x¹y³.
The y term in the expansion will be
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Empirical Rule.
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Testing if p1-p2 = 0.19, calculate the test statistic, z, where p^1 = 0.74 sampled from 75, and p^2 = 0.44
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In a famous study done in the 1960s two dolphins, Doris and Buzz, were trained to
work together to earn fish. Doris was shown a light underwater. If the light was on
steadily, her partner Buzz on the other side of the tank needed to press a button on
the right for them to earn fish. If the light was blinking, he needed to press a button
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At one point in the study, the researcher hung a canvas in the middle of the tank in
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near the curtain and began to whistle loudly. Shortly after that Buzz whistled back
and then pressed the [correct] button". (Tintle, Rossman and Chance, MAA Prep
Workshop)
Of course, getting it right once was not enough to convince the scientists that there
was really communication going on. It turned out, that in 15 out of 16 trials the
dolphin pushed the correct button.
Of course, it is possible that this happened just out of random chance - that the
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Reading My Progress, i-Ready
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tablet computer for $499 which is
off the regular price.
David wants to buy a new tablet computer. He looks at a sales ad and sees that a computer store is selling
Part A
Write an equation that represents the situation, Let x = the original cost of the tablet
Part B
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Let t be the time in seconds, 0
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- Test -2 (page 10 of 35) - Personal - Microsoft Edge Ô https://elearn.squ.edu.om/mod/quiz/attempt.php?attempt3D1894461&cmid%3890604&page=D9 SQU E-LEARNING SYSTEM (ACADEMIC) Business Statistics 1 || Spring21 Time left 1:49:10 Question 10 On average, you receive 2.6 pieces of junk mail a day. Assume that the number of pieces of junk mail you receive each day follows the Poisson distribution What is the expected number of pieces of junk mail you receive daily? Not yet answered Marked out of 6.20 1.00 F Flag question O b. 1.61 O c. 6.76 O d. 2.60arrow_forwardDifferentiate. y = eP(p + p/p)arrow_forward了 * 00 R Frequency cc.edu/webapps/assessment/take/launch.jsp?course_assessment_id=_842675_1&course_id%=_859154_1&content_id%3_19492605_1&step * Question Completion Status: QUESTION 1 The following histogram represents the number of body piercings for students in a statistics class. 40 0 2 4. 9 Number of Piercings 8 a. Is this graph symmetric or skewed? b. For this graph, is mean or median the best choice for the measure of center? c. For this graph, is standard deviation or IQR the best choice for the measure of variation? d. For this graph, the mean expected to be (higher than, lower than, or about the same as?) the median. QUESTION 2 Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save 2 étv MacBook Air DD F7 F8 08 F 4 F5 F3 2$ 4 #3 9. 6. 5. |arrow_forward
- 3:49 PM Sat Jan 30 MAT150 Online Assignment #1.docx Assignment #1 – How to use Calculator 1. If range is 60, number of class is 6, what is the class width? (Round up to next whole number) class width === 2. The data set is 2,4,5,7,10,15, what is sum Ex and the mean (Average)? (Round to the nearest tenth). Ex = 2+4+5+7+10+15 = (n is how many numbers there are) 3. If IQR is 0.69, find Usual Min and Usual Max? Usual Min = 0.68 – 1.5*IQR = Usual Max = 1.22 + 1.5*IQR = 4. Fill out the table below: H= 77.67 58 58 – 77.67 = -19.67 (-19.67)² = 386.9089 LL 5. Fill out the table below: x P(x) xP(x) x² x´p(x) 00.10 10.30 20.60 6. If , what is 7. If µ=5.5, o=0,1, n=16, what is a µ̟ and o̟? = 11 = *r. ==0 8. n= 150, o = 6,2, = 1 – 0.99 = 0.01, Z,= Z,005 = 2.575 SO0'0=1 pul Find 2.2 + E =. Find 2.2 – E =arrow_forwardRound to six decimal placesarrow_forward[Statistics] How do you solve this? Data: https://mcs.utm.utoronto.ca/~nosedal/data/cfcs.txt CFC 2 1 1 2 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 2 1 1 1 2 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 1 2 1 2 2 2 2 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 1 2 1 1 1 1 1 2 2 1 1 1 1 1 1 1 2 1 1 1 2 1 1 2 1 1 1 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 2 1 1 1 2 1 1 1 2 2 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 2 1 2 2 1 1 1 1 1 2 1 2 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 2 1 1 2 1 1 1 1 1 1 2 2 2 2 2 1 1 2 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1…arrow_forward
- [Statistics] How do you solve this? Data: https://mcs.utm.utoronto.ca/~nosedal/data/cfcs.txt CFC 2 1 1 2 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 2 1 1 1 2 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 1 2 1 2 2 2 2 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 1 2 1 1 1 1 1 2 2 1 1 1 1 1 1 1 2 1 1 1 2 1 1 2 1 1 1 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 2 1 1 1 2 1 1 1 2 2 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 2 1 2 2 1 1 1 1 1 2 1 2 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 2 1 1 2 1 1 1 1 1 1 2 2 2 2 2 1 1 2 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1…arrow_forward[Statistics] How do you solve this? Data: https://mcs.utm.utoronto.ca/~nosedal/data/cfcs.txt CFC 2 1 1 2 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 2 1 1 1 2 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 1 2 1 2 2 2 2 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 1 2 1 1 1 1 1 2 2 1 1 1 1 1 1 1 2 1 1 1 2 1 1 2 1 1 1 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 2 1 1 1 2 1 1 1 2 2 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 2 1 2 2 1 1 1 1 1 2 1 2 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 2 1 1 2 1 1 1 1 1 1 2 2 2 2 2 1 1 2 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1…arrow_forward[Statistics] How do you solve this? Data: https://mcs.utm.utoronto.ca/~nosedal/data/cfcs.txt CFC 2 1 1 2 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 2 1 1 1 2 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 1 2 1 2 2 2 2 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 2 1 2 1 1 1 1 1 2 2 1 1 1 1 1 1 1 2 1 1 1 2 1 1 2 1 1 1 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 2 1 1 1 2 1 1 1 2 2 1 2 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 1 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 2 1 2 2 1 1 1 1 1 2 1 2 1 1 1 2 1 1 1 2 1 1 1 1 2 1 2 2 1 1 2 1 1 1 1 1 1 2 2 2 2 2 1 1 2 1 1 1 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 1 1 2 1 1 1 1 2 1 2 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 2 1 1 2 1 1 1 1 1 2 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 2 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 2 1 1 1 1 1 2 1 2 1 1 1 1 1 1 1 1 1…arrow_forward
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