STAT 473 S24 Chapter 10 Quiz - Sample - Solutions

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Apr 3, 2024

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NAME: _____________________ STAT 473 Spring 2024 Chapter 10 Quiz – There is Trouble with the (Binomial) Trees While this quiz is being administered via Gradescope, you are expected to follow all instructions in this document. If you believe that a question is defective, write your reason on your quiz paper. Calculation type questions require supporting work to receive full credit. A question with a correct numerical answer – this includes zero, my hero - and no supporting work will receive zero credit. If you cheat on this quiz your semester grade for this course will be an F. Some examples of cheating are: Allowing another student to see your paper during the exam period. Looking at another student’s paper during the exam period. Using notes during the exam period. Looking at your phone during the exam period. Altering your answer to a question after your paper is graded and asking that your paper be re-graded. Regardless of all other instructions contained elsewhere in this quiz, the N in an N-period binomial tree is always three (3). If your quiz paper is not signed it will not be graded. I have read the statements on this page. I understand the statements on this page. Your Name (PRINT): ______________________________________________ Your Signature: __________________________________________________
NAME: _____________________ STAT 473 Spring 2024 Chapter 10 Quiz – There is Trouble with the (Binomial) Trees
NAME: _____________________ STAT 473 Spring 2024 Chapter 10 Quiz – There is Trouble with the (Binomial) Trees Given: r = 0.02, δ = 0.04, ơ = 0.15, n = 3, T = 0.75 h = T /n = 0.75 / 3 = 0.25 u = e (r-δ)h + ơ*SRT(h) = e (0.02 - 0.04)*0.25 + 0.15*SQRT(0.25) = 1.0725 d = e (r-δ)h - ơ*SRT(h) = e (0.02 - 0.04)*0.25 - 0.15*SQRT(0.25) = 0.9231 u S = S * e (r-δ)h + ơ*SRT(h) = 50 * e (0.02 – 0.04)*0.25 + 0.15*SQRT(0.25) = 50 * 1.0725 = 53.6254 d S = S * e (r-δ)h - ơ*SRT(h) = 50 * e (0.02 – 0.04)*0.25 - 0.15*SQRT(0.25) = 50 * 0.9231 = 46.1558 uu S = u S * 1.0725 = 57.5317 ud S = du S = u S * 0.9231 = d S * 1.0725 = 49.5025 dd S = d S * 0.9231 = 42.6072 uuu S = uu S * 1.0725 = 61.6839 uud S = uu S * 0.9231 = 53.0918 udd S = ud S * 0.9231 = 45.6966 ddd S = dd S * 0.9231 = 39.3314 C u = Max(0, 53.6254 – 45.00) = 8.6254 C d = Max(0, 46.1558 – 45.00) = 1.1558 C uu = Max(0, 57.5137 – 45.00) = 12.5137 C ud = Max(0, 49.5025 – 45.00) = 4.5025 C dd = Max(0, 42.6072 – 45.00) = 0 C uuu = Max(0, 61.6839 – 45.00) = 16.6839 C uud = Max(0, 53.0918 – 45.00) = 8.0918 C udd = Max(0, 45.6966 – 45.00) = 0.6966 C ddd = Max(0, 39.3314 – 45.00) = 0 p* = e (0.02-0.04)*0.25 – 0.9231 = 0.48126 1.0725 - 0.9231 Option Value (57.5137) = e -0.02 * 0.25 * [ (16.6839 * 0.48126) + (8.0918 * 0.51874) ] = 12.1659 Option Value (49.5025) = e -0.02 * 0.25 * [ (8.0918 * 0.48126) + (0.6966 * 0.51874) ] = 4.2344 Option Value (42.6072) = e -0.02 * 0.25 * [ (0.6966 * 0.48126) + (0.000 * 0.51874) ] = 0.3336 Option Value (57.5137) = Max(12.5737, 12.1659) = 12.5737 (Amer: Use Exercise Value since Greater) Option Value (49.5025) = Max(4.5025, 4.2344) = 4.5025 (Amer: Use Exercise Value since Greater) Option Value (53.6254) = e -0.02 * 0.25 * [ (12.5737 * 0.48126) + (4.5025 * 0.51874) ] = 8.3163 Option Value (46.1558) = e -0.02 * 0.25 * [ (4.5025 * 0.48126) + (0.3336 * 0.51874) ] = 2.3282 Option Value (53.6254) = Max(8.6254, 8.3163) = 8.6254 (Amer: Use Exercise Value since Greater) Option Value (50.000) = e -0.02 * 0.25 * [ (8.6254 * 0.48126) + (2.3282 * 0.51874) ] = 5.3321
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