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Jun 9, 2024

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Final Exam - Results Attempt 1 of 1 Written Apr 2, 2024 1:31 PM - Apr 2, 2024 3:39 PM Released Apr 3, 2024 12:00 PM Attempt Score 94.67 / 100 - 94.67 % Overall Grade (Highest Attempt) 94.67 / 100 - 94.67 % What is a Confidence Interval Question 1 3 / 3 points With 95% confidence, the program director estimated that the proportion of MGMT650 students that are very satisfied is 90% ± 5%. It's in the top 10% of all classes. What is a Confidence Interval The proportion of very satisfied students cannot be off by more than 5%. With 95% probability, the true proportion of very satisfied students falls between 85% and 95%. Loosely, we say with 95% confidence that the true proportion is somewhere between 85% and 95%. Actually, 95% of all possible confidence intervals contain the true proportion. There is a 5% probability that the true proportion of very satisfied students falls between 85% and 95%.
Question 2 3 / 3 points Answer: 0.54 Hide ques²on 2 feedback Margin of Error - Mean Question 3 4 / 4 points What is the margin of error for the population mean at 90% confidence level for the information in DATA (<--- Click the link to access the data for this problem.) With 80% confidence, for sample proportion 0.42 and sample size 28, what is the upper confidence limit with 2 decimal places? With 80% confidence, for sample proportion p and sample size n, the upper confidence limit is p + NORM.S.INV(1 - (1 - 0.80)/2) x SQRT( p(1-p)/n ) Margin Mean 0.72 0.76 None of the answers match my calculation. 0.75 0.74 0.73 0.71
Hide ques²on 3 feedback Question 4 3 / 3 points Answer: 327.10 Hide ques²on 4 feedback Confidence Interval - Test Mean Question 5 4 / 4 points Bobo's Bad Burgers fast food claims you will be in and out in 5 minutes. To test this claim, time in minutes from entering Bobo's to receiving the order was secretly recorded. The results are documented in DATA. At a 95% confidence level, does the confidence interval support Bobo's claim? For sample mean m, sample standard deviation s, and sample size n, the margin of error is =T.INV.2T(1 - 0.90, n - 1) x s/SQRT(n) With 90% confidence, for sample mean 323.50, sample standard deviation 12.60, and sample size 35, what is the upper confidence limit with 2 decimal places? With 90% confidence, for sample mean m, sample standard deviation s, and sample size 35, the upper confidence limit is m + ( T.INV.2T(1 - 0.90, 35 - 1) x s/SQRT(35) ) Confidence Interval - 1 The confidence limits (4.77,6.58) support the claim of 5 minutes. 5 falls inbetween the confidence limits. Bobo's performance meets the expectation.
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Question 6 3 / 3 points Match up the following: __ 4__ __ 1__ __ 3__ __ 2__ 1 . 2 . 3 . 4 . Question 7 4 / 4 points Match up the following: __ 2__ __ 1__ 1 . 2 . 3 . 4 . None of the answers match my calculation. The confidence limits (2.77, 4.54) reject the claim of 5 minutes. 5 is greater than the upper confidence limit. Bobo's performance is exemplary. The confidence limits (6.79,8.56) reject the claim of 5 minutes. 5 is less than the lower confidence limit. Audit of Bobo's procedures and employees is recommended. The confidence limits (1.62,3.21) reject the claim of 5 minutes. 5 is greater than the upper confidence limit. Performance at Bobo's is incredible. The risk we are willing to take of a type 1 error, or the type 1 error rate Rejection of H0 when H0 is true Rejection of H0 when H0 is false, or not rejecting H0 when H0 is true Failure to reject H0 when H0 is false Type 1 error Type 2 error Not an error The power of a test = P(rejecting H 0 |H 0 false) The probability of a type 2 error 1 - pvalue < H 0 : μ ≤ 0
__ 4__ __ 6__ __ 5__ __ 3__ 5 . 6 . Question 8 3 / 3 points Match the rules for rejecting H0 at the right to the following tests __ 3__ __ 2__ __ 4__ __ 1__ 1 . 2 . 3 . 4 . Question 9 3 / 3 points Match problems to procedures. Test of this hypothesis requires 1-tailed test with upper reject region Test of this hypothesis requires 2-tailed test with lower reject region bounded by negative critical value and upper reject region bounded by positive critical value Test of this hypothesis requires 1-tailed test with lower reject region bounded by negative critical value Reject H 0 H 0 : μ ≥ 0 H 0 : μ = 0 Two-tail test with lower and upper reject regions One-tail test with lower reject region For any test hypothesis, ANOVA, or Chi Squared, this rule for rejecting H0 always applies. One-tail test with upper reject region test statistic > positive critical value test statistic < negative critical value test statistic outside interval (negative critical value, positive critical value) pvalue <
__ 5__ __ 1__ __ 2__ 1 . 2 . 3 . 4 . 5 . Run times (msec) of a new phone app developed by GotYourGP and established competitor WeTrackYou.Inc. are logged in a data file. At = 0.05, are the run times of GotYourGP and WeTrackYou.Inc comparable? An effective vaccine would reduce the proportion of exposed persons contracting a disease. A pharmaceutical company wants to test the effectiveness of a new vaccine in preventing a certain disease. It is expected that 40% of unvaccinated exposed people will contract the disease. A group of 48 exposed persons volunteered to be vaccinated. Later, two of the volunteers contracted the disease. Test H0: π ≥ 0.40 (vaccine ineffective) at = 0.01. Given weights of 31, 29, 26, 33, 40, 28, 30, and 25, 1-tailed test of proportion with negative critical value 2-tailed test of mean with both negative and positive critical values 1-tailed test of mean with negative critical values 1-tailed test of paired-data with positive critical value 2-tailed test of means of 2 independent populations
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__ 3__ __ 4__ Question 10 3 / 3 points Match problems to procedures. __ 3__ __ 1__ 1 . 2 . 3 . 4 . at = 0.05 test that the population mean is 35. Test size C battery mean life is at least 25 hours. To test that a gasoline additive increases mileage, we compute mpg with additive minus mpg without additive for each car. If the mean of the differences is positive enough, action will be required to implement the additive. Do 2-way table classification labels matter? Data were gathered in an experiment comparing the effects of three insecticides in controlling a certain species of parasitic beetle. Each observation represents the number of such insects found dead in a certain fixed area treated with an insecticide. ANOVA Chi-square test of homogeneity Chi-square test of independence Chi-square test of goodness of fit
__ 2__ __ 4__ Test H0 - Proportion Question 11 4 / 4 points An Air Quality instrument logs 0 when standards are not met and 1 when standards are met. The log is saved to file DATA. First, compute the proportion meeting standards as the mean of Air Quality values. Second, at alpha = 0.10 (sensitive, exploratory), test the hypothesis that proportion of times that air quality meets standards is at least 90%. A multinomial probability distribution describes the distribution of counts across multiple levels of a variable. For each level of a variable, which is common to multiple populations, are the distributions the same. Does the data validate the normal probability distribution assumption? Proportion None of the answers match my calculation. The pvalue of 0.062 indicates that the data provide weak evidence against H0: π ≥ 0.90. H0 is rejected at = 0.10. The pvalue of 0.006 indicates that the data provide overwhelming evidence against H0: π ≥ 0.90. H0 is rejected at = 0.10. Send out an air quality alert. The pvalue of 0.022 indicates that the data provide strong evidence against H0: π ≥ 0.90. H0 is rejected at = 0.10. The status quo has changed.
Hide ques²on 11 feedback Test H0 - Mean Question 12 4 / 4 points The Lawnpoke Golf Association (LGA) has established rules that manufacturers of golf equipment must meet for their products to be acceptable for LGA events. BatOutaHell Balls uses a proprietary process to produce balls with a mean distances of 295 yards. BatOutaHell is concerned that if the mean distance falls below 295 yards, the word will get out and sales will sag. Further, if the mean distance exceeds 295 yards, their balls may be rejected by LGA. Measurements of the distances are recorded in DATA. At = 0.05, test the no action hypothesis that the balls have a mean distance of 295 yards. The pvalue of 0.966 indicates that the data provide insignificant evidence against H0: π ≥ 0.90. H0 is not rejected at = 0.10. The status quo remains unchanged. Detailed feedback available upon request. TestH0 - Mean The test statistics of 2.238 is greater than the critical value of 1.734, therefore H0 is rejected. It is reasonable to assume that the distance is not 295 yards. The test statistic -1.297 is inside the acceptance region (-2.101, +2.101). It does not exceed either the lower or upper critical values. The null hypothesis H0 is not rejected. The mean distance is about 295 yards. The test statistic is 3.003 and the critical value is 1.734, therefore the test statistic is greater than the critical value of 1.734 and the null hypothesis is rejected. The distance is not 295 yards.
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Hide ques²on 12 feedback Test H0 - Paired Data Question 13 4 / 4 points The Fast N' Hot food chain wants to test if their "Buy One, Get One Free" program increases customer traffic enough to support the cost of the program. For each of 15 stores, one day is selected at random to record customer traffic with the program in effect, and one day is selected at random to record customer traffic with program not in effect. The results of the experiment are documented in DATA. For each store, compute difference = traffic with program minus traffic without program. At = 0.05, test the hypothesis that the mean difference is at most 0 (at best the program makes no difference, or worse it decreases traffic) against the alternative that the mean difference > 0 (the program increases traffic). The test statistic of 1.908 is greater than the critical value of 1.734, therefore H0 is rejected. It is reasonable to assume that the distance is not 295 yards. None of the answers match my calculation. Detailed feedback available upon request. Test H0 - Paired The pvalue of 0.221 indicates that the data provide insignificant evidence against H0. H0 is not rejected at = 0.05. You decide to conclude the study and not to recommend the program. The pvalue of 0.033 provides strong evidence against H0. H0 is rejected at = 0.05. You decide to recommend further evaluation of the program. None of the answers match my calculation. The pvalue of 0.002 provides overwhelming evidence against H0. H0 is rejected at = 0.05. You decide that the program results in increased
Hide ques²on 13 feedback Test H0 - 2 Means Question 14 4 / 4 points BigDeal Real Estate surveyed prices per square foot in the valley and foothills of Hoke-a-mo, Utah. Based on BD's DATA, are prices per square foot equal at = 0.01 ? customer traffic, overall, and recommend the program be implemented. The pvalue rejects H0: Mean difference > 0. The pvalue of 0.084 provides weak evidence against H0. H0 is not rejected at = 0.05. You decide the evidence is not strong enough to recommend further evaluation of the program. Detailed feedback available upon request. Test H0 2Means The critical value is 2.977 since this is a two-tail scenario. The test statistic is 1.936. Since the test statistic < the critical value, the test statistic does not lie in the area of rejection. Do not reject the null hypothesis. The prices per square foot are equal at alpha = .01 The critical value is 2.977 since this is a two-tail scenario. The test statistic is 1.513. Since the test statistic < the critical value, the test statistic does not lie in the area of rejection. Do not reject the null hypothesis. The prices per square foot are equal at alpha = .01 The critical value is 2.977 since this is a two-tail scenario. The test statistic is 2.239. Since the test statistic < the critical value, the test statistic does not lie in the area of rejection. Do not reject the null hypothesis. The prices per square foot are equal at alpha = .01 The critical value is 2.977 since this is a two-tail scenario. The test statistic is 3.207. Since the test statistic > the critical value, the test
Hide ques²on 14 feedback ANOVA - 1 Question 15 4 / 4 points National Bearings manufactures bearings at plants located in Portland Oregon, Houston Texas, and Jacksonville Florida. To measure employee knowledge of Total Quality Management (TQM), six employees were randomly selected at each plant and tested. The test scores for these employees are given in DATA. Managers want to know if, on average, knowledge of TQM is equal across the 3 plants. Test equality of mean scores at = 0.05. statistic does lie in the area of rejection. Reject the null hypothesis. The prices per square foot are not equal at alpha = .01 None of the answers match my calculation. Detailed feedback available upon request. ANOVA - 1 The F value of 6.349 is > the F critical value of 3.682, therefore reject the equality of means. Knowledge of TQM is not equal across the 3 plants. The F value of 9 is > the F critical value of 3.682, therefore reject the equality of means. Knowledge of TQM is not equal across the 3 plants. The F value of 3.419 is < the F critical value of 3.682, therefore do not reject equality of means. Knowledge of TQM is equal across the 3 plants. None of the answers match my calculation. The F value of 1.326 is < the F critical value of 3.682, therefore do not reject equality of means. Knowledge of TQM is equal across the 3 plants.
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Hide ques²on 15 feedback ANOVA - 2 Question 16 4 / 4 points To test whether the mean time to mix a batch of adhesive is the same for machines produced by four manufacturers, TiteBondMax obtained DATA on the time (minutes) needed to mix the materials. Test whether the machines have equal mean mixing time at = 0.05. Hide ques²on 16 feedback Pivot Table Detailed feedback available upon request. ANOVA - 2 The data provide strong evidence against H0: Equal means at pvalue 0.013. The mixing machines are not all equal. The data provide extreme evidence against H0: Equal means at pvalue 0.001. The mixing machines are not all equal. None of the answers match my calculation. The data provide weak evidence against H0: Equal means at pvalue 0.072. Equality of means remains plausible. The pvalue 0.0001 is extreme evidence that the machines are not all the same. The data provide insignificant evidence against H0: Equal means at pvalue 0.514. The machine are considered equal. Detailed feedback available upon request. Pivot Table
Question 17 4 / 4 points To balance inventory at Otto's Optometry, customer Gender and Eye Condition were collected in DATA. Make a 2x2 pivot table with Gender in rows and Eye Condition in columns. The pivot table is Question 18 3 / 3 points Answer: 7.6 None of the answers match my table Given the following contingency table with category labels A, B, C, X, Y, and Z, what is the expected count with 1 decimal place in the joint category of C and X? X Y Z A 6 10 10 B 15 6 2 C 10 1 5
Hide ques²on 18 feedback ChiSquare - Critical Value Question 19 4 / 4 points What is the critical value for level of significance and table parameters in DATA? Hide ques²on 19 feedback Chi Square - Test of Independence Question 20 4 / 4 points DATA contains Part Quality data of three Suppliers. At = 0.05, does Part Quality depend on Supplier, or should the cheapest Supplier be chosen? Detailed feedback available upon request. ChiSquare - Critical Value 11.143 18.475 None of the answers match my calculation. 22.307 5.991 Feedback available upon request. ChiSquare - Test of Independence Pvalue of 0.039 rejects the assumption of independence of Part Quality and Supplier. Further supplier evaluation is recommended.
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Hide ques²on 20 feedback ChiSquare - Goodness of Fit Question 21 4 / 4 points A sales region has been divided into five territories, each of which was believed to have equal sales potential. The actual Sales Volume for several sampled days is logged in DATA. At = 0.05, do the territories have equal Sales Volume? Pvalue of 0.008 rejects the assumption of independence of Part Quality and Supplier. Further supplier evaluation is recommended. The assumption of independence of Part Quality and Supplier cannot be rejected. Choose the cheapest Supplier. None of the answers match my calculation. Pvalue of 0.0008 rejects the assumption of independence of Part Quality and Supplier. Further supplier evaluation is recommended. Detailed feedback available upon request. ChiSquare - Goodness of Fit None of the answers match my calculation. H0: Territories have equal Sales Volume is rejected with pvalue 0.041. The counts are not consistent with the model of equal proportions. Territories have unequal Sales Volume. H0: Territories have equal Sales Volume is not rejected with pvalue 0.334. The counts are consistent with the model of equal proportions. H0: Territories have equal Sales Volume is rejected with pvalue 0.012. The counts are not consistent with the model of equal proportions. Territories have unequal Sales Volume. H0: Territories have equal Sales Volume is not rejected with pvalue 0.074. The counts are consistent with the model of equal proportions.
Hide ques²on 21 feedback Correlation - Qualitative Assessment Question 22 4 / 4 points Scatter plots are used to discover relationships between variables. Using the corresponding measurements of variable1 and variable2 in DATA, plot variable1 vs. variable2 and describe the correlation between variable1 and variable2. Hide ques²on 22 feedback Correlation - Quantitative Evaluation Question 23 4 / 4 points Detailed feedback available upon request. Correlation - Qualitative Assessment The strength of the relationship is strong, but it is not linear. None of the answers accurately characterize the data. The relationship is linear, negative, and strong. The relationship is linear, positive, and strong. The strength of the relationship is moderate, linear, and negative. The strength of the relationship is moderate, linear, and positive. There is no relationship, or the strength of the relationship is very weak Detailed feedback available upon request. Correlation - Quantitative Evaluation
Correlation is used to discover relationships between variables. Evaluate the correlation between the variables in DATA. What is the correlation (round to 3 decimal digits)? Hide ques²on 23 feedback Question 24 2.667 / 4 points The equation of the regression line is Y = aX + b. Match the following symbols to the description to the right. __ 5__ __ 3__ (6) __ 6__ (3) __ 1__ __ 4__ __ 2__ 1 . 2 . 3 . 4 . None of the answers match my calculation. -0.008 0.984 -0.991 0.310 Detailed feedback available upon request. R b a X R 2 Y Denotes the variable plotted on the horizontal axis and called the explanatory or independent variable. Denotes the variable plotted on the vertical axis and is called the response or dependent variable. Denotes the slope of the regression line, or change in Y for a change in X of +1. The proportion of the variability of Y that is explained by or accountable to X.
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5 . 6 . Regression - Assumption Question 25 0 / 4 points You are required to setup a predictive equation involving variable 1 and variable 2. First, you plot the DATA to determine if linear regression applies. You decide Hide ques²on 25 feedback Regression - Interpret slope The strength and direction of the linear relationship between X and Y. Denotes the intercept, or elevation of the regression line at X=0. Regression - Assumptions Linear regression is not applicable because the point pattern is curvilinear (has a curve). Linear regression is not applicable because it appears that there are two linear patterns indicating that the data come from two populations. Linear regression is not useful because the points have no discernible pattern. You need more information before deciding to use linear regression. The linear regression equation will be very useful because the points have a strong linear pattern. Detailed feedback available upon request. Regression - Interpretation
Question 26 4 / 4 points An important application of regression in manufacturing is the estimation of cost of production. Based on DATA from Ajax Widgets relating cost (Y) to volume (X), what is the cost per widget? Hide ques²on 26 feedback Regression - Estimation Question 27 4 / 4 points An important application of regression in manufacturing is the estimation of cost of production. Based on DATA from Ajax Widgets relating cost (Y) to volume (X), what is the cost of producing 600 widgets? Hide ques²on 27 feedback 8.75 7.38 None of the answers match my calculation. 8.21 7.54 Detailed feedback available upon request. Regression - Estimation 6954 None of the answers match my calculation. 5206 5826 6312
Done Detailed feedback available upon request.
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