Phys 121A – 09 Physics Laboratory Report 7

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New Jersey Institute Of Technology *

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121A

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Physics

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Jan 9, 2024

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5

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Phys 121A – 09 Physics Laboratory Report #7 Lab 217: RC Circuits Kevin Butryn Rosa Roger, Sachiv Gupta 11/7/14 Zhaoqian Su 1. Objectives a. To observe and analyze the voltage across a capacitor Vc as a function of time t in a circuit obtaining a resistor and a capacitor in series 2. Theoretical Background a. Kirchhoffs first rule states that the sum of all currents entering a junction is the same as the sum of all currents leaving the junction. The loop rule follows from conservation of energy, as a charge passes along a loop and returns to its starting point the sum of the rises in the potential associated with the emf in the loop must equal the sum of the drops in potential associated with resistors or other circuit elements. 3. Procedure a. Set up the experiment as per book, and test different value of voltage, current for the various different circuits, and measure the voltage across the capacitor 4. Results
a. Experimental Data i. Part 1 1. Graphs and mat lab code are attached b. Calculation i. none c. Error Analysis i. none 5. Discussion and Questions a. none 6. Conclusions a. It takes a constant time for 23% of the capacitor to discharge and in the same time for 66% of the capacitor to be charged.
C=1000*10^-6; R=33*1000; V0=5; t=0:.01:200; tau=R*C; Vt=V0*exp(-t/tau); Yth=log(Vt/V0); texp=[0 5 10 15 20 30 40 50 60] Vexp=[5 4.4 3.9 3.5 3.1 2.5 2.0 1.6 1.3]; Yexp=log(Vexp/V0); subplot(2,1,1); plot(t, Vt, texp, Vexp, 'x'); subplot(2,1,1); plot(t, Yth, texp, Yexp, 'x') coefficients=polyfit(texp, Yexp,1); m=coefficients(1) tauexp=-1/m error=abs(tau-tauexp)/tau*100
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C=1000*10^6; R=33*1000; V0=5; t=0:.01:200; tau=R*C; Vt=V0*(1-exp(-t/tau)); Yth=log(1-Vt/V0); texp=[0 5 10 15 20 30 40 50 60]; Vexp=[0 .5 1.0 1.4 1.8 2.4 2.9 3.3 3.6]; Yexp=log(1-Vexp/V0); subplot(2,1,1); plot(t, Vt, texp, Vexp, 'x'); subplot(2,1,2); plot(t, Yth, texp, Yexp, 'x') coefficients=polyfit(texp, Yexp,1); m=coefficients(1) tauexp=-1/m error=abs(tau-tauexp)/tau*100

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