lab-8-mechanical-energy

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Lab 8: Mechanical Energy General Physics I: Mechanics (Illinois Institute of Technology) Scan to open on Studocu Studocu is not sponsored or endorsed by any college or university Lab 8: Mechanical Energy General Physics I: Mechanics (Illinois Institute of Technology) Scan to open on Studocu Studocu is not sponsored or endorsed by any college or university Downloaded by Aditya Kumar (artistadityakumar@gmail.com) lOMoARcPSD|36573830

Amelia Lobo PHYS 123 A20437425 Lab 8: Mechanical Energy (a) For the frst experiment, explain why work done by the falling mass is independent of the path taken. The work done is a conservatve force therefore it is independent of the path taken. The height at where the falling mass starts has an inital gravitatonal potental energy. How the object got to the inital height is irrelevant because it has the same gravitatonal potental energy and falls straight down. (b) What did the additon of a spring do to the overall system? Is this spring force a conservatve force? The cart on the track goes slower with the additon of the spring because potental energy from the falling mass is converted into elastc potental energy of the spring. The spring force is a conservatve force because it is independent of the path taken and only relies on the inital and fnal positons. (c) Write down the energy equaton relatons for the second experiment. m 2 g y i = 1 2 k x 2 + m 2 g y f , where m 2 is the mass on the air track, y i is the inital height of the falling mass, y f is the fnal height of the falling mass, k is the spring constant and x is the horizontal displacement. (d) Where does the maximum kinetc energy in parts 1 and 2 occur? The maximum kinetc energy in part one occurs when the falling mass is about to stop at its fnal positon. It occurs in part two just before the mass on the track stops (e) Can we truly ignore fricton in this lab? Explain using your data. Spring potental energy 0.01470511 0.0330865 0.0588204 4 Potental Energy 0.063765 0.0956475 0.12753 The spring potental energy and the potental energy of the falling mass should be equal because potental energy from the falling mass is converted into elastc potental energy of the spring. However, a lot of the energy is lost because the spring potental energy is always less then the falling mass potental energy. Therefore, fricton cannot be truly ignored because the energy “lost” is the force of fricton on the system. Downloaded by Aditya Kumar (artistadityakumar@gmail.com) lOMoARcPSD|36573830

Amelia Lobo PHYS 123 A20437425 (f) Calculate the rato of the kinetc and potental energies for parts 1 and 2. What do these ratos tell you about the conservaton of energy? Part 1: Kinetc Energy Potental Energy Rato 0.06739948 0.073575 0.91606495 0.08996121 0.0981 0.91703579 0.1120791 0.122625 0.91399878 Part 2: Kinetc Energy Potental Energy Rato 0.02643907 0.01470511 1.79795124 0.02553959 0.0330865 0.77190368 0.01442918 0.05882044 0.24530894 The ratos in part 1 are very close to 1.0. This shows that most of the conservaton was conserved. The potental and kinetc energies should be equal in order to conserve the energy therefore the ratos should be close to 1. In the second part of the experiment the ratos vary greatly and are not generally close to 1. This means that the energy was not conserved and much of the energy was “lost” by another force actng upon the system. (g) What efect would the release point have on the fnal velocity? The fnal velocity of the cart on the track will be much higher if the falling mass is released from a higher point. Downloaded by Aditya Kumar (artistadityakumar@gmail.com) lOMoARcPSD|36573830

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