Exercise 3,4,5,6,7
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Jan 9, 2024
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Mitchell Spangle
PSH 104 Lab
EXERCISE 3,4,5,6,7
1.)
Start with the given value: 46.0 g. Then divide the given value by 1000 to convert grams to
kilograms: 46.0 g / 1000 = 0.046 kg. Therefore, 46.0 grams is equal to 0.046 kilograms.
2.)
Start with the given value: 57 seconds. Then divide the given value by 60 to convert seconds to
minutes: 57 seconds / 60 = 0.95 minutes. Therefore, 57 seconds is equal to 0.95 minutes.
3.)
Start with the given value: 13.5 cm. Then divide the given value by 2.54 to convert centimeters
to inches: 13.5 cm / 2.54 = 5.31 inches (rounded to two decimal places). Therefore, 13.5
centimeters is approximately equal to 5.31 inches.
4.)
Start with the given value: 47 °F. Then subtract 32 from the given value: 47 °F - 32 = 15 °F. Then
divide the result by 1.8 to convert Fahrenheit to Celsius: 15 °F / 1.8 ≈ 8.33 °C (rounded to two
decimal places). Therefore, 47 °F is approximately equal to 8.33 °C.
--- EXERCISE 4 ---
1.) Both
2.) Accurate
3.) Accurate
4.) Accurate
5.) Neither
--- EXERCISE 5 ---
1.)
The number 405000 has five significant digits: 4, 0, 5, 0, and 0
2.)
The number 0.0098 has two significant digits: 9 and 8.
Mitchell Spangle
PSH 104 Lab
EXERCISE 3,4,5,6,7
3.)
The number 39.999999 has eight significant digits: 3, 9, 9, 9, 9, 9, 9, and 9.
4.)
The number 13.00 has four significant digits: 1, 3, 0, and 0.
5.)
The number 80,000,089 has eight significant digits: 8, 0, 0, 0, 0, 0, 0, and 9.
6.)
The number 55,430.00 has six significant digits: 5, 5, 4, 3, 0, and 0.
7.)
The number 0.000033 has two significant digits: 3 and 3.
8.)
The number 620.03080 has eight significant digits: 6, 2, 0, 0, 3, 0, 8, and 0
--- PART 2 ---
1.)
The number 70,000,000,000 can be written in scientific notation as 7.0 x 10
^10
2.)
The number 0.000000048 can be written in scientific notation as 4.8 x 10
^-8
3.)
The number 67,890,000 can be written in scientific notation as 6.789 x 10
^7
4.)
The number 70,500 can be written in scientific notation as 7.05 x 10
^4
5.)
The number 450,900,800 can be written in scientific notation as 4.509008 x 10
^8
6.)
The number 0.009045 can be written in scientific notation as 9.045 x 10
^-3
7.)
The number 0.023 can be written in scientific notation as 2.3 x 10
^-2
Mitchell Spangle
PSH 104 Lab
EXERCISE 3,4,5,6,7
--- EXERSICE 6---
1.)
In this scenario, the son guessed that the dad was holding 81 cents, but the dad actually had 90
cents. First, we calculate the difference between the guessed value and the actual value: |81 -
90| = 9 Then, we divide the absolute difference by the actual value: 9 / 90 = 0.1 Next, we
multiply the result by 100 to find the percent error: 0.1 x 100 = 10 The percent error is 10%.
Since the percent error is greater than the allowed 5% error, the son did not guess close enough
to get the money.
2.)
In this scenario, Jennifer and Johnny determined the velocity of the car to be 34.87 m/s, while
the actual velocity is 34.15 m/s. First, we calculate the difference between the measured value
and the actual value: |34.87 - 34.15| = 0.72 Then, we divide the absolute difference by the
actual value: 0.72 / 34.15 = 0.0211 Next, we multiply the result by 100 to find the percent error:
0.0211 x 100 = 2.11 The percent error is 2.11%. Since the percent error is less than the allowed
2.5% error, Jennifer and Johnny will pass their final project. Their measured value is within the
acceptable range of error set by the teacher.
3.)
In this scenario, the expected trip duration is 3.15 hours, but the actual duration is 3.26 hours.
First, we calculate the difference between the measured value and the actual value: |3.26 -
3.15| = 0.11 Then, we divide the absolute difference by the actual value: 0.11 / 3.15 = 0.0349
Next, we multiply the result by 100 to find the percent error: 0.0349 x 100 = 3.49 The percent
error is 3.49%. Since the percent error is slightly higher than the allowed 3% error, the train
company did not live up to its reputation on this trip. The actual trip duration exceeded the
expected duration by more than the specified margin of error.
4.)
In this scenario, Tommy ended the season with a batting average of 0.258, while the desired
batting average, within a 7% error, is 0.275. First, we calculate the difference between the
measured value and the actual value: |0.258 - 0.275| = 0.017 Then, we divide the absolute
difference by the actual value: 0.017 / 0.275 = 0.0618 Next, we multiply the result by 100 to find
the percent error: 0.0618 x 100 = 6.18 The percent error is 6.18%. Since the percent error is
greater than the allowed 7% error, Tommy did not have a great season according to his coach's
criteria. His batting average falls below the desired range, indicating that he did not meet the
coach's expectation.
--- EXERCISE 7 ---
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Mitchell Spangle
PSH 104 Lab
EXERCISE 3,4,5,6,7
1.)
A. The independent variable in this experiment is the habitat space, which refers to the different
sized aquariums used for the fish populations.
B. The dependent variable in this experiment is the number of surviving fish. This variable is
dependent on the habitat space and will be measured at the end of the experiment.
C. The controls in this experiment include: - Same type and amount of food: By keeping the food
consistent across all aquariums, the researchers ensure that the only difference among the
habitats is the space available. - Equally maintained and cleaned aquariums: Maintaining and
cleaning the aquariums equally ensures that the cleanliness and conditions within the habitats
do not affect the fish populations differently. - Constant water temperature: By keeping the
water temperature constant, the researchers eliminate the variable of temperature as a
potential factor influencing the fish populations.
2.)
A. The independent variable in this experiment is the habitat space, which refers to the different
sized aquariums used for the fish populations.
B. The dependent variable in this experiment is the number of surviving fish. This variable is
dependent on the habitat space and will be measured at the end of the experiment.
C. The controls in this experiment include: - Same type and amount of food: By keeping the food
consistent across all aquariums, the researchers ensure that the only difference among the
habitats is the space available. - Equally maintained and cleaned aquariums: Maintaining and
cleaning the aquariums equally ensures that the cleanliness and conditions within the habitats
do not affect the fish populations differently. - Constant water temperature: By keeping the
water temperature constant, the researchers eliminate the variable of temperature as a
potential factor influencing the fish populations.