Kami Export - ANSWERS%20Geometric%20Proofs%20pkt

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Ridge Community High School *

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Mathematics

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Nov 24, 2024

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Name ‘k‘ E \/ Date Class Practice A Za 8l Geometric Proof Write the letter of the correct justification next to each step. J I N\s (Use one justification twice.) ! Given: HJ is the bisector of ZIHK and £1 = /3. e E3H 1. HJ is the bisector of £IHK. B A. Definition of £ bisector L L2=21 fi B. Given L. L1=43 [% £2=/3 Ina__ 1o - tolumn EIESESIN C. Transitive Prop. of = proof, each step in the proof is on the left and the reason for the step is on the right. Fill in the blanks with the justifications and steps listed to complete the two-column proof. Use this list to complete the proof. L1=22 Def. of straight £ Z1 and £2 are straight angles. \K 6. Given: Z1 and £2 are straight angles. / 2, Prove: £1=£2 Proof: Statements Reasons fallandl2 Qe Steanig i (}nglig’ 1. Given 2.m«£1=180° m£2 = 180° 2.b. _def. of S-hmghfé'fi 3. ms£1=mxsL2 3. Subst. Prop. of = 4.c. L=l T 4. Def. of = £ Follow the plan to fill in the blanks in the two-column proof. 7. Given: £1 and £2 form a linear pair, and £3 and £4 form a linear pair. Prove: mZ1 + mZ£2 + m4£3 + m«£4 = 360° Plan: The Linear Pair Theorem shows that £1 and £2 are supplementary and £3 and £4 are supplementary. The definition of supplementary says that mZ£1+m«£2 =180° and m«£3 + m£4 = 180°. Use the Addition Property of Equality to make the conclusion. Statements Reasons 1. £1 and £2 form a linear pair, and £3 and £4 form a linear pair. la _ (Qive~ J £3 and Z4 are supplementary. 2. Z1 and £2 are supplementary, and 2b Lontar Pair Thm . sl tmt2=1° M3+ mlY=1£0 3. Def. of supp. 4 4. mZ1+m£2 + m£L3 + ms£4 = 360° 4.d. _Add pmp- G = Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. 2-43 Holt Geometry
Name K \/ Date Class Practice B 28 Geometric Proof Write a justification for each step. Given: AB = EF, B is the midpoint of AC, and E is the midpoint of DF . 1. B is the midpoint of R, and E is the midpoint of DF . . AB=BC,and DE =EF . . AB=BC, and DE = EF. 4, AB+BC=AC, and DE + EF = DF. 5. 2AB=AC, and 2EF = DF. (o) . AB=EF . 2AB=2EF o) . AC=DF . AC=DF Fill in the blanks to complete the two-column proof. 10. Given: ZHKJ is a straight angle. KI bisects ZHKJ. c)'f mid poinT def. of congryent Seq . add. post - s siHuhen POE 5 W.{’ n ( pttu ) ‘l’\flu\lf . Poe Subst. Poc def of congruenct Prove: ZIKJ is a right angle. Proof: Statements Reasons t.a._L HKT is g &atfht angle [1.Given 2. mZHKJ = 180° 2.b. __(od{ ot Shaughht L 3.0 K1 hoedS LHKT 3. Given 4. ZIKJ = ZIKH 4. Def. of £ bisector 5. mZIKJ = mzIKH 5. Def. of = 4 6.d._MLTKT+ M LT¢H” m/ HKT |6 £ Add. Post. 7. 2mZIKJ = 180° 7.e.Subst. (Steps 2 .S, b ) 8. m«IKJ = 90° 8. Div. Prop. of = 9. ZIKJis a right angle. o.f._cuf of right ¢ Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. 2-44 Holt Geometry
Name (\ E\/ Date Class Practice C 28 Geometric Proof Write a two-column proof. 1. Given: The sum of the angle measures in a triangle is 180°. , Prove: m£1=m<3 + mz4 o e, Sty mend S J usShicainon o . = 2 €N O wlL2r4mL3tm Ld=1%0 (Q 9 W“ —~ o Q& 2) gwitin @ L1 f\,\ath‘»;;r“ = 2 0 L ~ 5 [ingar f N G/\ Linear pasl Thm (D LianalZ are Q0T 7 ot of opp!. @ mel Ame2 s : @ substriwhon P06 G mLZtmi3tmiY=miitmlZ @/‘ Subtr, PoE - A 4+mLY =md) N T ~ ©C:ff rYl\fYL\LT = MLSFTmeY 67 }’.\’ s POC 2. Peter drives on a straight road and stops at an intersection. The intersecting road is also straight. Peter notices that one of the angles formed by the intersection is a right angle. He concludes that the other three angles must also be right angles. Draw a diagram and write a two-column proof to show that Peter is correct. | X Skate mends & .,.__VS+\'{{‘ cation @ il 12l @) [j(vUT i @/l.‘mfi'(-c‘& = /T . righ ANy \ O 21 vsa right angle @ gree3 S & LI andt2 cre & limear /%.”"(29“’{N Z 2 andlD arta linar par (D subst. 7 | and!l d are o lindar pair . e I o Q5> /3 1SAa B Ll analZ art Supp! B Linsa | orightt L2 andl Sare Sv’lflp'. f (‘3, (U‘[ o LL ane l ¥4 areig-;}apl. @ [)(JZ/-U/\SU'OPL ' o ,(}-hf[, B wiiAmi2 =18 . mL2 t mL 2@ /g(c))e; . O B j - mL l, .4 (TC? l ) def. of r/ifq‘( = B % Z;C%l " mLZ =160° (D/ Su bstrhcon RO s Y 2 b c , - [ OU i (‘0 1 '“LL/' ) Ig /‘(AOG C’)\/ S b‘f'Y_ POC A me2=q0° el 10 —n T okt L) LQ@ L2 and L4 Gre rght L's®) ded. of mght L's riginal content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. @\) L P R are yertieald 'S 2-45 (G) Gve o : Holt Geometry (o /1% /13 i ouf. of verticel LS | )
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Name ) K E y Date Class Problem Solving Y2 Geometric Proof 1. Refer to the diagram of the stained-glass window and use the given plan to write a two-column proof. Given: Z1 and £3 are supplementary. £2 and £4 are supplementary. L3=/4 b Prove: Z1=./2 4 | % Plan: Use the definition of supplementary angles to write \; y the given information in terms of angle measures. Then use the Substitution Property of Equality and the Subtraction Property of Equality to conclude that £1 = 22, @) o il Y 4 &L}DP" (’:” (j‘(\ffl,\, LZ, LY are SUPF', " | (2 melrmL- 1 80° @ deof ) Spp'. = 1§0° mcel? miYy =l . B ) 2 =mL2 ¥y (’) sl St - POE é”mLI\‘rnc% M A é L3=L4 @/Cj'\l’e.o\ p (s% me3 =med 6’/ (fi{f‘o.' 1%5 T‘\/ Y= me2+mey Q:) Su ST - Q) Sdlotr . prop of 553 ® dod (8 (cmg‘r The position of a sprinter at the starting blocks is shown in the diagram. Which statement can be proved using the given information? Choose the best answer. 2. Given: Z1 and £4 are right angles. A £3=/45 C m4£1+m«4 =90° B1=s4 ) D ms3+ms5=180° 3. Given: £2 and £3 are supplementary. £2 and £5 are supplementary. /‘ \/ H 43 and £5 are complementary. J Z1 and £2 are supplementary. Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. 2-49 Holt Geometry
Name K l: \; Date Class Challenge L2l Prove It! In a proof, you can often determine the Given information from the figure. Write the information that is given in each figure. Then make a conjecture about what you could prove using the given information oA Guen: L1214 JABC savigni L __Guen: £F ZET, F6=TH Du ovt: L2 = L 3 (answeds Prove - E—flH = E—'—j |’Y\At1 V- fd ) 3. Write a two-column proof. @ P i Given: ZKLM and ZNML are right angles. £2=/3 Prove: /1=z=/4 - L‘2 3“M O LKLM , LUML are nghtl's @ g\e~ Q L KLM ELNML @ Light L Thm, B mLKLM = mLNML Ll e gt é\) M L KLM=mel ime 2 © angle acd . pait . LY MMM ZmedTm | Q Subst. prop-Pph- . (6; Glvein O L2223 =7 ~ O mers e uit 6) mMLr+me2 = mMe2 +tmeH (®) Sub ] X m @ Subtr. Po€ @ | = mlLYy nza/ &Ly (D sty & ©) et #mea 2mestmed Original content Copyright © by Holt McDougal. Additions and changes to the original content are the responsibility of the instructor. 2-48 Holt Geometry