Assignment 13
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School
Straighterline *
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Course
250
Subject
Mathematics
Date
Nov 24, 2024
Type
Pages
5
Uploaded by supabrown
Name • Tianna tBlasco
Couse
MAC 2312
Rropessor
Cn. Greorge
kapkoulis
STO
JOate
6361629
o31l2023
Assi
ą
nment t* 13
laylor 'blyoormials
Pabem
13.4
n
2;3,4
anck)Va)
Soluhon
(x-
Ttantz), (2) =
k!
Kec
tan "%) =Sec(x)
ton
(x)
=2sex) tan(x)
tan
() =4se?()ton?cx)+ 2sec(x)
tan"(x) :
see)tan'cx)tlbse (z)tan(2)
tan)=2
5tan
)4
ton
=12
tan()
4on ) :30
Hence
(-/4)
+
(x) =
+ 2
4
12 31
yron2), T/4
=| +2)+2(x-+2-#+ a-
Tasent,(x)= 1+2(
) +2(2-A)+ 2(2-)
(X)= 1+2(x-
4)t2
(e-#)*
n)n (3)-1-+ 2lx-)
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Roobum
13.10
Soluthon
B
nnci+o,o (2)
T, (X)
)))
kl
Co)
k
a
+)o) =o
22
|ncit)
=x
-2x+ 2
(nit ))o)=2
1(x) o
+
x
roblem
13.1|
n ,2
3oluh'on
Pix)
(x)
let
pk)
()
Keo
T, ()
=
+
T(x)
=
|+ x2
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roblem
13.12
Tn,
(x)
n
2}
let
Pt) = e
kI
pmase
So
(-a
k
1
-a)
=e
k
Ror
n=12
Problem
13.13
(x)
Kor
2nd
Tayle
Poiyngmv'el
lit
-
n
-n,f()
k
31
+2
30
e2 ()
14
) =4
Thus
T2(2) =31+ 30 (e-2) + 3
( -2)2
14
=31+
30 (
-2)
+
1(x-2)
(
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Padlem
13.14
roleet
n(3x' -5x'
+6x
Qs
8 inganhy
o (3x-Sy'+ o)
= 3o(x2) -5o(x) + 6 o()
= elx)
+ o(x')
o(x)- o()
Rr n
2
o(x)
o (x*)+ o(x) + o(x)
(2)
(o (e)
|(o(era)
•(c*)
o (f(x)
.o (fx>)
o Ecx>)
)
o(f(x)
o(f())
= occ)
o(o (ties)*)J
ofirn)o(tas)
-ofo((Ecz)))]
o((Aoo)')
(alo(3
+ 6x'+ 5) a
+ 5x)
3o(x^)
+ 6o (')+ So (e)
2-20
4)
x
+ o(oe5))es 2c-
→
o+o(s3)
= • (o)+ o(olx))
o(x3)
+ o(LS)
>o
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roblem 13.14
o((to(x))),
(s)
as
(o (ioc)) ) : o(tet»)
(21+ oG))*)
=
ol+
2x
+ o(x4))
o(x*) +2o(x°) + olocx"))
o(x)
+
o(x)
+
o()
•() o()+
Prololem
13-15
+o(Cgex)
")
+ (z + (1)
|since = o()
=
+ +
5 +o(x)
(x
+
Sineo)
we
hoos
+
+
n=2
3)
+
+
+
Sinca
=0)
we chopse
+
+
+
n2
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