Chapters-12&14-2023

pdf

School

The University of Sydney *

*We aren’t endorsed by this school

Course

1362

Subject

Material Science

Date

Oct 30, 2023

Type

pdf

Pages

34

Uploaded by DeaconOysterPerson821

Report
Chapter 12 - 1 ISSUES TO ADDRESS... Structures of ceramic materials: How do they differ from those of metals? Chapters 12&14: Structures of Ceramics and Polymers What are the basic microstructural features ? How are polymer properties effected by molecular weight ? How do polymeric crystals accommodate the polymer chain?
Chapter 12 - 2 Callister study guide. 12.1 – 12.2: Study all parts Chapter 12: Structures & Properties of Ceramics 12.3: Only need to know Si-O tetrahedron 14.1 – 14.3: Study all parts 14.4: Only need to know those presented in lecture 14.5, 14.7, 14.9 –14.12: Study all parts
Chapter 12 - 3 Examples of Ceramics
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 4 Examples of Advanced Ceramics Ferroelectric materials for memories Microelectromechanical Systems (MEMS)
Chapter 12 - 5 Ceramics vs Metals Difference? elements bonding conductivity mechanical properties brittle metallic + non-metallic, non-metallic + non-metallic single non-metallic element (C, Si) ionic, ionic + covalent, covalent (Si) Poor conductivity (insulator, semiconductor) many more…
Chapter 12 - 6 Ceramic Crystal Structures Mainly ionic bonding with some covalent bonding Cations – Positively charged metallic ions Anions – Negatively charged nonmetallic ions Electrical neutrality – net charge = 0 Ex: Na 1+ Cl 1- , Ca 2+ F 2 1- Size effect – determine the maximize # of nearest oppositely charged neighbors - - - - + unstable - - - - + stable - - - - + stable (Smallest stable size) (not always true but we will not discuss other situations) ß
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 7 Coordination # increases with Coordination # and Ionic Radii 2 r cation r anion Coord # < 0.155 0.155 - 0.225 0.225 - 0.414 0.414 - 0.732 0.732 - 1.0 3 4 6 8 linear triangular T D O H cubic . . ZnS (zincblende) NaCl (sodium chloride) CsCl (cesium chloride) r cation r anion Issue: How many anions can you arrange around a cation? Note: exceptions occur! The lower end value of radius ratio range is determined by the corresponding coordination number.
Chapter 12 - 8 An example of Cation Site Size Determination Determine minimum r cation /r anion for O H site (C.N. = 6) a = 2 r anion 2 r anion + 2 r cation = 2 2 r anion r anion + r cation = 2 r anion r cation = ( 2 - 1) r anion 2 r anion + 2 r cation = 2 a 414 0 anion cation . r r = (determination of the lower end of the size range)
Chapter 12 - 9 AX Crystal Structures -- NaCl Example: NaCl (rock salt) structure MgO and FeO r Na = 0.102 nm r Na / r Cl = 0.564 \ cations prefer O H sites r Cl = 0.181 nm Can be treated as Na fcc + Cl fcc with the displacement of <100>/2 between the two lattices Coordination # = 6
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 10 AX Crystal Structures -- CsCl 939 . 0 181 . 0 170 . 0 Cl Cs = = - + r r Cesium Chloride structure: \ cubic sites preferred So each Cs + has 8 neighboring Cl - Can be treated as Cs sc + Cl sc with the displacement of <111>/2 between the two lattices Coordination # = 8
Chapter 12 - 11 ABX 3 Crystal Structures • Perovskite Ex: complex oxide BaTiO 3 Perovskite units can be found in many important ceramic functional materials
Chapter 12 - 12 Most common elements on earth are Si & O Silicate Ceramics Si 4+ O 2- The basic unit of silicate, with -4 charge associated with it More covalent character than ionic Quartz: crystalline Glass fibre: amorphous
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 13 Ceramic Density Computation A A C N V ) A A ( n C S + S ¢ = r Number of formula units/unit cell Volume of unit cell where A = atomic weight (can be found in Fig. 2.6) V C = Volume of unit cell = a 3 for cubic N A = Avogadro’s number = 6.022 x 10 23 atoms/mol Density = r = Cell Unit of Volume Total Cell Unit in Atoms of Mass V C N A n A r = Compare: = weight of an atom
Chapter 12 - 14 What is a Polymer? Poly mer many repeat unit C C C C C C H H H H H H H H H H H H Polyethylene (PE) Cl Cl Cl C C C C C C H H H H H H H H H Poly(vinyl chloride) (PVC) H H H H H H Polypropylene (PP) C C C C C C CH 3 H H CH 3 CH 3 H repeat unit repeat unit repeat unit Macromolecules monomer = The small molecule from which a polymer is synthesized. 14
Chapter 12 - 15 Polymer Composition Most polymers are hydrocarbons – i.e., made up of H and C Methane 14
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 16 Most polymers are hydrocarbons – i.e., made up of H and C Saturated hydrocarbons Each carbon singly bonded to four other atoms – Example: Ethane, C 2 H 6 C C H H H H H H Saturated Hydrocarbons 14
Chapter 12 - 17 14
Chapter 12 - 18 Unsaturated Hydrocarbons Double & triple bonds somewhat unstable – can form new bonds Double bond found in ethylene or ethene - C 2 H 4 Triple bond found in acetylene or ethyne - C 2 H 2 C C H H H H C C H H 14
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 19 Isomerism Isomerism ( Do you remember “allotropy/polymorphism”? ) two compounds with same chemical formula can have quite different structures for example: C 8 H 18 • normal-octane • 2,4-dimethylhexane C C C C C C C C H H H H H H H H H H H H H H H H H H H 3 C CH 2 CH 2 CH 2 CH 2 CH 2 CH 2 CH 3 = H 3 C CH CH 3 CH 2 CH CH 2 CH 3 CH 3 H 3 C CH 2 CH 3 ( ) 6 ß 14
Chapter 12 - 20 Polymer Chemistry Silicones 14
Chapter 12 - 21 Chemistry and Structure of Polyethylene Note: polyethylene is a long-chain hydrocarbon - paraffin wax for candles is short polyethylene bond angle = 109.5 ° 14
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 22 MOLECULAR WEIGHT Molecular weight , M : Mass of a mole of chains. Low M high M Not all chains in a polymer are of the same length — i.e., there is a distribution of molecular weights (Sometimes called molecular mass, molar mass) 14
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 23 x i = number fraction of chains in size range i M n = total wt of polymer total #of molecules MOLECULAR WEIGHT DISTRIBUTION M n = Σ x i M i M W = Σ w i M i w i = weight fraction of chains in size range i M i = mean (middle) molecular weight of size range i Number-average molecular weight: ࠵? ࠵? Weight-average molecular weigh: ࠵? ࠵? 14 Important
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 24 Molecular Weight Calculation Example: average mass of a class Student Weight mass (lb) 1 104 2 116 3 140 4 143 5 180 6 182 7 191 8 220 9 225 10 380 What is the average weight of the students in this class: a) Based on the number fraction of students in each mass range? b) Based on the weight fraction of students in each mass range? 14
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 25 Molecular Weight Calculation (cont.) Solution: The first step is to sort the students into weight ranges. Using 40 lb ranges gives the following table: weight number of mean range students weight N i W i mass (lb) mass (lb) 81-120 2 110 121-160 2 142 161-200 3 184 201-240 2 223 241-280 0 - 281-320 0 - 321-360 0 - 361-400 1 380 Σ N i Σ N i W i 10 1881 total number total weight Calculate the number and weight fraction of students in each weight range as follows: x i = N i N i w i = N i W i N i W i For example: for the 81-120 lb range x 81 120 = 2 10 = 0.2 w 81 120 = 2 x 110 1881 = 0.117 14
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - M w = w i M i = (0.117 x 110 + 0.150 x 142 + 0.294 x 184 + 0.237 x 223 + 0.202 x 380) = 218 lb M n = x i M i = (0.2 x 110 + 0.2 x 142 + 0.3 x 184 + 0.2 x 223 + 0.1 x 380) = 188 lb 26 Molecular Weight Calculation (cont.) weight mean number weight range weight fraction fraction W i x i w i mass (lb) mass (lb) 81-120 110 0.2 0.117 121-160 142 0.2 0.150 161-200 184 0.3 0.294 201-240 223 0.2 0.237 241-280 - 0 0.000 281-320 - 0 0.000 321-360 - 0 0.000 361-400 380 0.1 0.202 M w = w i M i = 218 lb 14
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 27 Degree of Polymerization, DP DP = average number of repeat units per chain where m = average molecular weight of repeat unit for copolymers this is calculated as follows: m = Σ f i m i C C C C C C C C H H H H H H H H H H H H H H H H H C C C C H H H H H H H H H ( ) DP = 6 mol. wt of repeat unit i Chain fraction DP = M n m An alternative way of expressing the average chain size of a polymer is DP 14
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 28 Effect of Molecular Weight on Mechanical Properties 14
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 29 Molecular Structures for Polymers B ranched Cross-Linked Network Linear secondary bonding 14
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 30 Thermoplastic and Thermosetting Thermoplastic - soften when heated and harden when cooled (secondary bonding diminished through molecular motion) - the hardening and softening are reversible processes - relatively soft - most linear and branched polymers - common ones are polyethylene, polystyrene and polyvinylchloride Thermosetting - become hard during formation and do not soften on heating - network polymers – extensive covalent cross-links between chains - 10-50% of chain repeat units are cross-linked - Generally harder and stronger with better dimensional stability than thermoplastics - Vulcanised rubbers, epoxies, and some polyester resins (understanding the meaning is enough) 14
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
31 Copolymers two or more monomers polymerized together random – A and B randomly positioned along chain alternating – A and B alternate in polymer chain block – large blocks of A units alternate with large blocks of B units graft – chains of B units grafted onto A backbone A – B – random block graft alternating 14
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 32 Crystallinity in Polymers Ordered atomic arrangements involving molecular chains Crystal structures in terms of unit cells Example shown polyethylene unit cell 14
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 33 Polymer Crystallinity (cont.) Polymers rarely 100% crystalline Difficult for all regions of all chains to become aligned Degree of crystallinity expressed as % crystallinity . -- Some physical properties depend on % crystallinity. -- Heat treating causes crystalline regions to grow and % crystallinity to increase. crystalline region amorphous region % crystallinity 100 ) ( ) ( ´ = - - a a r r r r r r c s s c ࠵? ! is the density of fully crystalline structure ࠵? " is the density of fully amorphous structure ࠵? # is the density of the specimen concerned 14
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
Chapter 12 - 34 Ceramic materials have covalent & ionic bonding. Structures are based on: -- charge neutrality -- maximizing # of nearest oppositely charged neighbors. Structures may be predicted based on the ratio of the cation and anion radii. Polymer molecules – very large molecular chains that are composed of repeat units along the chain. Polymer molecules can be characterized by their size (molecular weight), shape (chain twisting, coiling, bending) , and structure (linear, branched, crosslinked, network). Polymers can be partially crystallized. Percent crystallinity depends on processing condition, chemistry and structure of the polymers. Summary
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help

Browse Popular Homework Q&A

Q: 15. In the diagram below, label the type of circuit represented by each part of the installation,…
Q: Convert each of the following to degrees and minutes.   16.25  0
Q: A circular channel (n = 0.013) has a diameter of 4.75 ft and is laid on a slope of 0.5%. The flow…
Q: 2. The following table gives the cumulative distribution function (cdf) of a discrete random…
Q: According to a study, 73% of all males between the ages of 18 and 24 live at home. (Unmarried…
Q: How touse Python to implement an alternative approximate match using the Levenshtein edit distance?
Q: Proctor and Gamble's total amount of debt increased from 31.9% in March 2011 to 34.2% in December…
Q: Choose the reagent that can accomplish the following transformation: 1) BH3 2) NaOH/H₂O2/H₂O H₂/Pd…
Q: 6. Find the rank of the matrix 2031 0211 3211 54 53 A=
Q: Consider tan (3/I – 5) = -1. We wish to determine all solutions for this problem. First solve the…
Q: How to use Python to  implement a recursive function with signature find(path, filename) that…
Q: 4. Using the Laplace transform pairs of Table 2.1 and the Laplace transform theorems of Table 2.2,…
Q: For each compound in the table below, decide whether there would be any hydrogen-bonding force…
Q: Arrange these elements according to first ionization energy. Highest ionization energy Kr Br As Se…
Q: 3. Suppose 100 independent random y values are each distributed Pois(1) - poisson distribution with…
Q: A sample of hydrogen contains 35.3 grams. 1. How many moles of H atoms are there in the sample? 2.…
Q: When I put data from a spreadsheet into a Word document.  Give a disadvantage of just copying that…
Q: How does sociology help us understand propaganda better? I.e. what is going on sociologically with…
Q: A student reported the mass of ten glass beads as 2.507 ± 0.015 g. What should the student report as…
Q: A compound is found to contain 3.622 % carbon and 96.38 % bromine by mass. To answer the question,…
Q: analyze why and how slavery became such a divisive issue in the years following the missouri…
Q: Average Age and Length of Service Is the average age of armed services personnel related to the…