DA 2 - Probability and Simulation
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Oregon State University, Corvallis *
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314
Subject
Geology
Date
Feb 20, 2024
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docx
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3
Uploaded by MajorFlowerShark29
ST 314 Data Analysis 2
Probability and Simulation
Question 1
heads tails 57 43
Question 2
sim_unfair_coin
heads tails 22 78
Question 3
> die <- c("one", "two", "three", "four", "five", "six")
> roll <- sample(die, 10, replace=TRUE)
> table(roll)
roll
five four one six three two 2 1 1 3 2 1
Question 4
> sim_uf_die <- sample(die, size=10, replace=TRUE, prob=c(.1,.2,.3,.1,.2,.1))
> sim_uf_die
[1] "six" "three" "three" "two" "three" "three" "five" "four" "two" [10] "three"
> table(sim_uf_die
+ )
sim_uf_die
five four six three two 1 1 1 5 2
one=10%, two=20%, three=30%, four= 10%, five= 20%, six=10%
Question 5
ST 314 Data Analysis 2
a.
.2125 > P_Ordering2_Granite <- .25
> P_Ordering2_Basalt <- .2
> P_Granite <- .25
> P_Basalt <- .75
> P_Ordering2 <- P_Ordering2_Granite * P_Granite + P_Ordering2_Basalt * P_Basalt
> print(P_Ordering2)
[1] 0.2125
b.
.7059
P(B|Ordering 2)= (P(Ordering 2|B) * P(B))/P(Ordering 2)
P(B|Ordering 2)= (.2x.75)/.2125
P(B|Ordering 2)= .7059
c.
.225, .6667,.3333
P(Ordering 1) = P(Ordering 1|G) * P(G) + P(Ordering 1|B) * P(B)
P(Ordering 1)= .6*.25+.1*.75
P(Ordering 1) = .225
P(G|Ordering 1)= (P(Ordering 1|G) * P(G))/P(Ordering 1)
P(G|Ordering 1)= (.6*.25)/.225
P(G|Ordering 1)= .6667
P(B| Ordering 1) = (P(Ordering 1|B) * P(B))/P(Ordering 1)
P(B| Ordering 1) = .1*.75/.225
P(B|Ordering 1)= .3333
Question 6
a.
.75
b.
.25
c.
.45
d.
.1
e.
.3077
ST 314 Data Analysis 2
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