11.10.2

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Lab - Design and Implement a VLSM Addressing Scheme Examine Network Requirements Determine how many host addresses and subnets are available Q1. How many host addresses are available in a /25 network? Ans. 32-25 = 7 (number of bits on host portion) 2^7-2 = 126 (number of hosts) Q2. What is the total number of host addresses needed in the topology diagram? Ans. 40+25+5+4+4+2 = 80 hosts Q3. How many subnets are needed in the network topology? Ans. 6 subnets Determine the largest subnet Q4. What is the subnet description (e.g. BR1 LAN or BR1-BR2 link)? Ans. BR1 LAN Q5. How many IP addresses are required in the largest subnet? Ans. 40 IP Addresses Q6. What subnet mask can support that many host addresses? Ans. n=6 (number of host) 2^6-2 = 62 32-6 = 26 (Prefix for new subnet mask or bits for networking portion) 255.255.255.192 /26 Q7. How many total host addresses can that subnet mask support? Ans. 32-26 = 6 2^6-2 = 62

Q8. Can you subnet the 192.168.33.128/25 network address to support this subnet? Ans. YES Determine the second largest subnet Q9. What is the subnet description? Ans. BR2 LAN Q10. How many IP addresses are required for the second largest subnet? Ans. 25 hosts Q11. What subnet mask can support that many host addresses? Ans. 27 Q12. How many total host addresses can that subnet mask support? Ans. 30 Q13. Can you subnet the remaining subnet again and still support this subnet? Ans. YES Q14. What are the network addresses that would result from this subnetting? Ans. 192.168.33.192/27 and 192.168.33.224/27 Determine the third largest subnet Q15. What is the subnet description? Ans. BR2 IOT LAN Q16. How many IP addresses are required for the next largest subnet? Ans. 5 hosts Q17. What subnet mask can support that many host addresses? Ans. 29 Q18. How many total host addresses can that subnet mask support? Ans. 6

Q19. Can you subnet the remaining subnet again and still support this subnet? Ans. YES Q20. What are the network addresses that would result from this subnetting? Ans. 192.168.33.224/29, 192.168.33.232/29, 192.168.33.240/29 and 192.168.33.248/29 Determine the fourth largest subnet Q21. What is the subnet description? Ans. BR1-BR2 Link Q22. How many IP addresses are required for the next largest subnet? Ans. 2 Q23. What subnet mask can support that many host addresses? Ans. 30 Q24. How many total host addresses can that subnet mask support? Ans. 2 Q25. Can you subnet the remaining subnet again and still support this subnet? Ans. YES Q26. What are the network addresses that would result from this subnetting? Ans. 192.168.33.248/30 and 192.168.33.252/30 Design the VLSM Address Scheme Calculate the subnet information. Subnet Description Number of Hosts Needed Network Address /CIDR First Host Address Broadcast Address BR1 LAN 40 192.168.33.128/25 192.168.33.12 9 192.168.33.191 BR2 LAN 25 192.168.33.192/27 192.168.33.19 3 192.168.33.223

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BR2 IOT LAN 5 192.168.33.224/29 192.16833.225 192.168.33.231 BR2 CCTV LAN 4 192.168.33.232/29 192.168.33.23 3 192.168.33.239 BR2 HVAC C2 LAN 4 192.168.33.240/29 192.168.33.24 1 192.168.33.247 BR1-BR2 Link 2 192.168.33.248/30 192.168.33.24 9 192.168.33.251 Cable and Configure the IPv4 Network Configure basic settings on each router

Test Connectivity From BR1, ping BR2’s G0/0/0 interface. From BR2, ping BR1’s G0/0/0 interface

Reflection Question Q. Can you think of a shortcut for calculating the network addresses of consecutive / 30 subnets? A /30 network has 4 address spaces: the network address, 2 host addresses, and a broadcast address. A /30 network has 4 address spaces: the network address, 2 host addresses, and a broadcast address. A /30 network has 4 address spaces: the network address, 2 host addresses, and a broadcast address. Ans. A /30 network has 4 address spaces: the network address, 2 host addresses, and a broadcast address.

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