HW4

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New Jersey Institute Of Technology *

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350

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Computer Science

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Feb 20, 2024

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1. Following the style of Practice Problem 3.1 (page.182), assume the following values are stored at the indicated memory addresses and registers: Addres s Valu e - - Registe r Value 0x1000 0xAA - - %rdi 0x100 0 0x1004 0xBB - - %rsi 0x1 0x1008 0xCC - - %rdx 0x2 0x100C 0xD D - - %rcx 0x4 Fill in the following table showing the values for the indicated operands: Operand Value %rdi 0x100 0 0x1004 0xBB $0x1008 0x100 8 (%rdi) 0xAA 4(%rdi) 0xBB 8(%rdi,%rcx) 0xDD 0x1002(%rdx, %rcx) 0xCC -4(%rdi,%rsi,4) 0xAA (%rdi,%rdx,4) 0xCC
2 .Using the Address and Register table in Problem 1, fill in the table below showing the values for the indicated operands (similar to Practice Problem 3.8 of page 194): Instruction Destinatio n Value addq (%rdi),%rsi %rsi 0x100 1 andq %rsi,%rdi %rdi 0x00 subq %rsi,(%rdi) 0x1000 0xA9 incq %rsi %rsi 0x2 decq %rdx %rdx 0x1 xorq (%rdi,%rdx,4),%rcx %rcx 0x100 C orq 0x1002(%rdx,%rcx), %rsi %rsi 0xCE 3 For the unknown assembly shown below, fill in the missing return statement in the C function unknown. unknown: imulq %rdx, %rsi leaq (%rsi,%rdi), %rax 8. ret long unknown(long x, long y, long z) { return __ (x+y) + z __________________________; } unknown: movq %rdi, %rax salq $3, %rax addq %rdi, %rax ret long unknown(long x) { return ___8x+x_________________________; }
4 Do problem 3.58 which says "Write C code for the assembly shown in the problem." #include <stdio.h> long decode2 (long, long, long); int main(){ long x,y,z,n; printf("\nEnter the value of x:"); scanf("%1ld",&x); printf(" "); printf(" \nEnter the value of y:"); scanf("%1ld",&y); printf ("\nEnter the value of z:"); scanf("%1ld",&z); n=decode2(x,y,z);
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printf("\nThe result ofdecode2(%1ld,%1ld,%1ld) is %1ld\n", x,y,z,n); return 0; } long decode2(long x, long y, long z) { long r; y=y-z; x=x*y; r=y; r=r<<63; r=r>>63; r=r^x; return r; }
5 Write an assembly program to perform the C function below using the following register assignment: x:rdi; y:rsi, z:rdx, t1:rcx, t2:rdi, t3:rsi, t4:rax No credit will be given to the ones with stack addresses. long arith(long x, long y, long z) { long t1,t2,t3,t4; t1 = x + y; t2 = t1 - z; t3 = t1 & t2; 20. t4 = t2 * t3; 21. return t4; } 5) arith: leaq (%rsi,%rdi), %rcx # t1 movq %rcx, %rdi subq %rdx, %rdi # t2 movq %rcx, %rsi andq %rdi, %rsi # t3 movq %rdi, %rax mulq %rsi, %rax # t4 ret
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