Lab 6

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Lab 6: Double Displacement Reactions Jernellee Palacio Chemistry 101 Professor Floruti October 12, 2023

Lab Partner: Carolyn Saad Introduction In this lab, we will be observing the chemical changes of double displacement reactions. A double-displacement reaction occurs when two compounds exchange cations and anions thus forming a new compound. An example of a double displacement reaction is NaCl +AgNO3 →AgCl + NaNO3. The sodium ion (Na ) from sodium chloride switches places with the silver ⁺ ion (Ag ) from silver nitrate. This results in silver chloride (AgCl) and sodium nitrate (NaNO3). ⁺ Abstract In this lab, we will be mixing solutions containing different compounds to observe the formation of new compounds. If a new compound forms, then a double displacement reaction occurs. The evidence of a double displacement reaction is a distinctive color change, precipitate, the breakdown of a solid, gas formation, and a temperature change. If no reaction occurs, then a double displacement reaction has not occurred. Materials Test tube rack, Medium sized test-tube, graduated cylinder, test-tube holder, distilled water Methods- Procedure Proper lab PPE -lab coat, goggles, long pants, closed toe shoes- must be always worn. Carefully gather eight test tubes and place them in a test tube rack. Rise all test tubes with tap water however the final rinse should be with distilled water. Each experiment requires a mixture of two solutions. Retrieved the solution required for this experiment from the table in your lab book. Take two test tubes and add 1.0 mL of each solution in each test tube. Return to lab bench and mix the solution. If a reaction occurs, record the results. If no reaction occurs note down no reaction or NR. Repeat steps 2 and 3 for each experiment. At the end of the experiment, clean

and rise tubes then place back to original place. Dispose of the solutions a in its the appropriate waste container. Reaction Table Reaction Mixture Evidence of Reaction 1. Aqueous ammonia solution and copper (II) nitrate Light blue 2. Barium chloride and ammonium sulfate White, precipitate at the bottom of test tube 3. Calcium chloride and silver nitrate White cloudy, precipitate 4. Barium chloride and calcium chloride NR 5. 3 M sodium hydroxide and 6 M hydrochloric acid Temperature change- Hot 6. Sodium carbonate and 6 M hydrochloric acid Fizzling and bubbles 7. 3 M sodium hydroxide and Iron (III) chloride Color change. Deep rust color. And deposits at the down. 8. Zinc nitrate and copper (II) nitrate Light blue Discussion: Chemical Equation 1.) 2(NH3) +Cu (NO3)2→ 2NH3(NO3) + Cu light blue/color change 2.) BrCl2+(NH4)2 (SO4) → Ba (SO4) +2(NH4) Cl color change-White precipitate 3.) CaCl2+ 2Ag (NO3) → Ca (NO3) 2+2AgCl White cloudy, precipitate 4.) BaCl2+CaCl2 → BaCl2+CaCl2 NR 5.) Na2OH+HCl → H20 + 2NaCl Temperature Change-Hot 6.) Na2(CO3) +2HCl →2NaCl +2H(CO3) Fizzling and bubbles

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7.) 3NaOH+3FeCl → 3NaCl+3Fe (OH) Color change to deep rust with precipitate 8.) ZN(NO3)2+Cu (NO3)2→ ZN(NO3)2+Cu(NO3)2 Color change -Light blue Conclusion In conclusion, a double displacement reaction occurs when two compounds exchange anions and cations to form a new compound. Importantly, a reaction only occurs when there is observable evidence. This new compound is shown through chemical changes such as color change, precipitate, the breakdown of a solid, gas formation and/or temperature change.

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