SYTHESIS OF CYCLOHEXENE

Help with the CHEM Lab report please! It is about Volumetric Analysis  There is also a Burn trail please make sure for that!

1.Calculate/find Limiting reagent: 2. Theoretical mass: 3.Percentage yield: 4.% recovery: （Reagents：acetone and benzaldehyde. Product；dibenzalacetone）

Mass of vial + cap + isopentyl alcohol: 28.999g Mass of vial + cap: 24.825 Mass of isopentyl alcohol used (g): 4.174 g Moles of isopentyl alcohol used (mol) 0.0478 mol Volume of acetic acid used: 7.00mL Mass of acetic acid used (g) (d = 1.05 g/mL): 7.35 g Moles of acetic acid used (mol): 0.124 mol Select the limiting reagent  A. Isopentyl  B. Acetic acid Isopentyl acetate theoretical yield (g)? Mass of isopentyl acetate obtained: 7.202 g Isopentyl acetate percent yield (%)?

Need help to calculate for percentage % recovery

please help

Below you will find five reaction products (labeled product 1, product 2, etc.), but you will only find four reaction schemes. Your job is to match the reaction scheme with the correct product. Simply fill in the blank with the product number (i.e. 1,2,3,4, or 5). Then, state the regio-control that governs the reaction (i.e. Markovnikov or anti-Markovnikov). If the reaction does not have any regio-control then enter none. OH X Product 1 iocontrol: Product 2 1. Hg(OAc)2, H₂O 2. NaBH4 $ -OH do % Product 3 OH to 4- Product 4 OH OH Product 5 700 hp

1. Answer the following questions based on the table: Pickling Vinegar Conc NaOH (M) 0.1005 Trial #1 Trial #2 Trail #3 Trial #4 Volume Vinegar (mL) 2.00 2.00 2.00 2.00 Initial Volume NaOH (mL) 0.32mL 0.22 1.02 0.44 Final Volume (mL) 24.25mL 24.20 25.00 24.45 Volume NaOH added (mL) 23.93mL 23.98mL 23.98mL 24.01mL a) Calculate the Average Volume NaOH used...show the trials that have %difference within 1% of each other. If you need to discard any trials- make sure to note this. b) Mass percentage of acetic acid in vinegar using your average volume of NaOH from Q1: (include a balanced reaction equation and show all work) c) % error calculation. Show ybur work in full. See Appendix B for details. (Reminder: Regular vinegar is 5.25% listed on bottle, pickling vinegar is 7.34% listed on bottle) d) In the titration of vinegar, a student uses 12.36 mL of NaOH(aq) (Molarity 0.100 M) to titrate a 2.00 mL sample of vinegar. If the student used lithium hydroxide (Molarity: 0.200 M) instead, what…

Mass of vial + cap + isopentyl alcohol: 28.999g Mass of vial + cap: 24.825 Mass of isopentyl alcohol used (g) ? Moles of isopentyl alcohol used (mol) ? Volume of acetic acid used: 7.00mL Mass of acetic acid used (g) (d = 1.05 g/mL) ? Moles of acetic acid used (mol) ?

2 2 points A stock solution of red dye solution is in a reagent hood ready to be used in the reaction. Molarity of red dye stock solution = 2.8 x 10-5 mol/L The experiment is carried out with the following volumes (Vol) of reagents: Vol of dye solution (mL) 2.5 Vol of CIO solution (mL) Vol of deionized water (mL) 10.0 17.5 Total volume of the reaction solution in the test tube is therefore 30.0 mL. The dilution equation is M1V1 = M2V2. What is the concentration of red dye, in units of mol/L, in the reaction mixture (in the test tube) at the start of the reaction? 2.2 × 10-6 mol/L 2.5 x 10-6 mol/L 2.8 x 106 mol/L 2.3 x 10-6 mol/L

Molar Mass (g/mole) Density (g/mL) Equivalent (ratio) Reagent Salicylic acid Amount Mole 138.12 Acetic anhydride 102.1 1.08 Sulfuric acid 98 1.8 catalyst

Please help with question 6,7,8

Concentration of Reagents (NH4)2S2O8 KI Na2S2O3 0.25 M 0.22 M 0.19 M Volumes of Solutions S₂082 (mL) Starch soln (mL) KNO3 (mL) EDTA soln (mL) KI (mL) S₂O32- (mL) x 5 9.7 0.9 26.4 0.5 9.9 1.1 Using the above data determine the concentration of I at the moment the reaction begins. HINT: This is a mixing problem. Determine the total number of moles of I and divide this amount by the total volume (in L). Be careful... If you go back and try this exercise again the values will change. Read the question carefully! Answer:

Just b

= STATES OF MATTER Applying like dissolves like For each solute, click the button under the better solvent. H H HO U C solute H I 2 CIH Η 2=0 CaC1₂ H H CH₂ - CH₂-OH Which is the better solvent? CH₂(CH₂) CH3 H₂O CH₂ CH₂OH :0: || CH₂- - CH3 I CH CC14 CH₂OH - CH3 0/5

I need help with portions e and f of this question

2-Methylcyclohexanol (5 mL, d=0.929g g/ml, MW= 114.19) was heated under reflux with 5mL of 85% phosphoric acid. What is the theoretical yield of the product for this reaction? a) 4.5 g     b) 3.9g    c) 3.2g    d) 2.9g    e) 2.5g

Find the theoretical yield and percent yield of Isopentyl Acetate (banana oil) 3.38g acetic acid used 1.88g isopentyl alcohol .5 ml sulfiric acid  Final yield: 1.31g of isopentyl acetate (banana oil) Please show steps, thank you!