ch-3

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101

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Chemistry

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Nov 24, 2024

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A force P =350N. 0 =25° is applied to move the shown rectangular block m = 80 kg, L =1.5 m) which is supported on two rollers at A and B. Case y’ 339 == I: H=0.75L. Case 2: H=Hmaximum so that the block not tip over. Given P 2L =10 n/s”, Choose the correct answers B A 39 Required A B c D i The acceleration of the block 365 3965|4274 [ass4 2] Reaction at roller A [N] 3927|3207 [2727 [3447 31 ! [Reaction at roller B [N] EEN I EC A N 7] “The block velocity after 2 sec 793 [1433_ [o421 [s427 5 H Maximum [m] 755 [5.098 2692 [2.186 6 |case 2 [[Reaction at roller A [N] 550 [1542 oot 6521 7] Reaction at roller B [N] 419 3023|3628 [605 Scanned with CamScanner
7/ BIET N YISO TR W _ Po3mN 25 Hedo Qs Gy W=-75L - Case @y W=HaX— o 38006 LHa O oy _ Crai® ke SOBE I L 1L b L CYHD BB “‘ e MA- -3206.55. > 3207 - Mo Vet ok N34 LA%2=T83 T NAENE. HA 43500820 MR 5= Nhx75 + 3500261 e 30D 4 x-785 =0 ,@-1;: o Gse Oy Wax s RS B, Sron @ A T W \ ,h.L:..uz R~ .w;..@“_o.xi\\i..\! ) MA=bsg. SR O . Madabeg U Scanned with CamScanner
A force P = . and an external moment M=45N.M. is applied to move the shown block (m = 80 kg. BC = 9 m and AB =1.5 m) on rough surface. The block is supported on two rollers at A and B. The friction coefficient is (u=0.2 ). Case 1:h = 0.5*AB. Case 2: cakulate hmin and hmax so that the block not tip over. Given g=10 m/'s”. Choose the correct answers 8 The acceleration of the block 2.71 2.375 9 |Case 1 |Reaction at roller A [N] 341.3 4082 1 | 10 [Reaction at roller B [N] 3 3828|3095 3583 | 1] e 2 [H Maximum (m] 3.221 245 2663 2064 ] 12 H Minimum [m] 0786|063 0682|0838 | Scanned with CamScanner
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In Problem 371, A uniform block ABCD (24 kg. Lx3L m, L=1.05) is loaded on two rollers on the back of the shown truck and connected in the cabinet by rod BE. Given 0=35 degrees, study the motion of the block. Case (1): The truck starts motion with acceleration a=2.7 m/sec2 and the block not tip over. Case (2): The truck start motion with the max. accel. (a max.) so that the block not tip over. Assume g=10 m's* 13 Case The tension in the cable BE [N] 85.1 79.11 73.12 97.07 14 (I). The normal reaction component at A [N] 193.3 171.8 161.1 204.1 15 The normal reaction component at D[N] 21.3 19.7 24.3 25.9 16 The max. acceleration of the truck [m/sec2] 2.651 3.561 4.016 3.333 17|Case [The tension in the cable BE [N] 97.66 118.8 76.54 90.62 18{(2) [The normal reaction component at A [N] 296 356.9 336.6 255.5 19 [The normal reaction component at D [N} 3.7 4.93 0 6.17 Scanned with CamScanner
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‘The uniform 8kg bar AB (L.=1.5m) shown is free to rotate in a vertical plane about a smooth pin at its end A. The body polar moment of Inertia Ig=1.5. The motion started when 0=30" with 0=2 rad/sec due to coupk C=7.5Nm. Case(1) at initial condition, case(2) when 0 reaches70” where g=10 m/s” 31 [The total accekeration at G 8549 [7482__[90.083___[8.015 32|Case 1 [The total Reaction at A 6175|6937 __|60.13___[73.99 33 Reaction angke with horizontal 1624|1413 [1202 1729 34 o 3071|3296 |3.555 __[3.813 35|Casc 2 [The total accekeration at G 1371107 1145 [9.198 36| [The total Reaction at A 1509 1969 1624 1395 37 Reaction angle with horizontal 912 1182|1343 [1102 Scanned with CamScanner
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