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Biology

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Apr 3, 2024

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Meena Amiri 2/18/24 1. (5 points - SHOW YOUR WORK) Demonstrate if/how selection can lead to a violation of the Hardy-Weinberg equilibrium principle. Assume initial allele frequencies of A1 = 0.6 and A2 = 0.4, an initial population size of 100, and selection removing 50% of heterozygous individuals. The genotype frequencies before and after selection should be calculated: Using the hardy-weinberg equation: p^2+2pq+q^2=1 p= 0.6, q=0.4 So the initial genotype frequencies are: p^2= (0.6)^2 =0.36 2pq= 2(0.6)(0.4)= 0.48 q^2= (0.4)^2= 0.16 So, the initial genotype frequencies are: AA = 0.36, Aa = 0.48, aa = 0.16 Number of individuals with genotype AA: 0.36×100=36 Number of individuals with genotype Aa:0.48×100=48 Number of individuals with genotype aa: 0.16×100=16 Apply selection removing 50% of heterozygous individuals: 48×0.5=24 Recalculating the allele frequencies after selection: Total number of individuals after selection: 36+24+16=76 Frequency of allele A1: (36×2+24)/(76×2)=96/152≈0.6329 Frequency of allele A2: 1−0.6329=0.3671 Recalculate the genotype frequencies after selection: p^2= (0.6329)^2= 0.4001 2pq= 2(0.6329)(0.3671)= 0.4643 q^2= (0.3671)^2≈0.1351 So, the genotype frequencies after selection are: AA ≈ 0.4001, Aa ≈ 0.4643, aa ≈ 0.1351 Before selection: AA = 0.36, Aa = 0.48, aa = 0.16 After selection: AA ≈ 0.4001, Aa ≈ 0.4643, aa ≈ 0.1351 As we can see, the genotype frequencies have changed after selection, indicating a violation of the Hardy-Weinberg equilibrium principle.
2. (5 points - SHOW YOUR WORK) Lidicker and McCollum provided a test of the hypothesis that the bottleneck in California sea otter populations led to inbreeding. One of the alleles they studied had just two alleles, S (for slow) and F (for fast). Among the 33 otters they sampled, the number of each genotype was: SS = 16, SF = 7, FF = 10 a. Within this sample, what are the frequencies of the S and F alleles? Total number of alleles = 33 * 2 = 66 (since each individual has two alleles) Calculate the frequency of allele S (p) using the genotype counts: Frequency of allele S (p) = (2 * SS + SF) / (2 * total number of alleles) Frequency of allele S (p) = (2 * 16 + 7) / (2 * 66) Frequency of allele S (p) = (32 + 7) / 66 Frequency of allele S (p) = 39 / 66 Frequency of allele S (p) ≈ 0.5909 Calculate the frequency of allele F (q) using the genotype counts: Frequency of allele F (q) = (2 * FF + SF) / (2 * total number of alleles) Frequency of allele F (q) = (2 * 10 + 7) / (2 * 66) Frequency of allele F (q) = (20 + 7) / 66 Frequency of allele F (q) = 27 / 66 Frequency of allele F (q) ≈ 0.4091 within this sample, the frequencies of the S and F alleles are approximately 0.5909 and 0.4091 b. Based on those allele frequencies, what are the EXPECTED Hardy-Weinberg genotype frequencies if the population is in equilibrium? Using the hardy-weinberg equation: p^2+2pq+q^2=1 P 2 =(0.5909)^2 ≈0.3483 2 pq =2(0.5909)(0.4091)≈0.4826 q 2 =(0.4091)^2 ≈0.167 So, SS ≈ 0.3483, SF ≈ 0.4826, FF ≈ 0.1674
c. What are the actual genotype frequencies from the 33 otters that were sampled? The actual genotype frequencies from the 33 otters sampled were SS = 16 SF = 7 FF = 10 d. Was the population in Hardy-Weinberg equilibrium? If not, does the data support inbreeding as an explanation and, if so, why? Given that the calculation of the expected genotype frequencies does not precisely match the provided observed genotype frequencies, we would expect some deviation from HWE. Whether this deviation is significant enough to suggest inbreeding would depend on the results of the chi-square test and further analysis. If the observed frequencies significantly differ from the expected frequencies and there are fewer heterozygotes than expected, it could support the hypothesis of inbreeding in the population.
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