Lab. 7
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University of Nebraska, Omaha *
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001
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Astronomy
Date
May 2, 2024
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4
Uploaded by DeanRiverKudu24
Lab 7 Apparent and Absolute Magnitude NAME SCORE 125 PROBLEMS TO COMPLETE FOR APPARENT MAGNITUDE—SHOW WORK HERE AND PUT ANSWERS ON WORKSHEET AT END OF THIS WORKSHEET. 1) The apparent magnitude of the Sun is -26.7 and Sirius is -1.52. How many times brighter is the Sun than Sirius? 26.7-1.52=25.8 2.512725.8=20917346213 The sun is 20917346213 times brighter. 2) On a certain evening, the apparent magnitude of Venus is — 4.3 and the apparent magnitude of Mars is -2.2. How many times brighter is Venus than Mars? 4.3-2.2=2.1 2.51272.1=6.91 Venus is 6.91 times brighter. 3) How many times brighter is Sirius at -1.52 magnitudes than a star that is magnitude 8.2? 2.512" (8.2+1.52) =7589 4) How many times brighter is a Full Moon, with an apparent magnitude of -12.6, than a dim magnitude +12.6 galaxy? 2.512725.2=12036349881.4 5) What is the theoretical limiting visual apparent magnitude of a 200-inch telescope? 9+5log (200) =20.5 Scanned with CamScanner
PROBLEMS TO COMPLETE FOR ABSOLUTE MAGNITUDE 6) What is the absolute magnitude of a star that is 87 pc from Earth, whose apparent magnitude is +5.50? AM=5.5+5-(5loge87) =5.5+5-(5xlog (87)) 0.8024037369 7) What is the apparent magnitude of a star called AX2, if d = 70 parsecs and M = - 8.1? -8.1=X+5-(5*log (70)) -8.1-5+(5*log (70)) =x X=-3.87450979993 8) What is the modulus of a star whose apparent magnitude is +4.91 and its absolute magnitude is +2.66? 4.91-2.66=2.25 9) How distant is a star whose modulus is -7.5? -7.5=5log(d)-5 -7.5+5=5log(d) Log(d)=-.5 D=.31622776601 10) If its apparent magnitude (m) = +13.5 and absolute magnitude (M) = +10, what is the distance 10 a star? 10=13.5=+5-(5*log(x)) (5*log(x)) =13.5+5-10 Log(X)=1.7 X=50.1187233627 Scanned with CamScanner
PROBLEMS TO COMPLETE FOR PARALLAX 11) A star has a parallax of .025 seconds of arc—what is its distance in parsecs? The nearest star has a parallax of .76 arc seconds—what is its distance in light years? 1/.025=40 parsccs 1/.76*3.26=4.28947368421 light years 12) If star were 2.40 pc from Earth, what would its distance be in AU? 1/x=2.40 1=2.40x 1/2.4=x X=.4166666666 41666666666*206265=85943.7499986AU 13) A star is 250 parsecs from us — what is its parallax angle? 1/x=250 1=250X X=1/250 .004 Scanned with CamScanner
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LAB 7 ANSWER SHEET 1)The sun is 20917346213 times brighter 2) Venus is 6.91 times brighter 3) 7589 4) 12036349881.4 5)20.5 6) 0.8024037369 7) X=-3.87450979993 8)2.25 9) D=.31622776601 10 X=50.1187233627 11) a. 40 parsecs b. 428947368421 light years 12) 85943.7499986AU | 13) .004 Scanned with CamScanner