HW#2 – Solar and Wind Design_
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San Jose State University *
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Subject
Aerospace Engineering
Date
Apr 3, 2024
Type
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Uploaded by AdmiralJackalMaster1084
HW#2 – Solar and Wind Design Spring 2024
Date Due: Wed. March 6, 2024 – upload to Canvas by 11:59 pm
Name #1:___Gabriel Colin ______________ Student ID:____016078790 ______________ Name #2:____Dylan LaDeroute _____ Student ID:____016828929
______________ Circle LECTURE Section: Sect.01 (12:00) or Sect.02 (3:00)
Gabriel is in Section 2 and Dylan is in Section 01
You should complete the homework with a partner
. Partners MUST work TOGETHER to complete it. This DOES NOT mean one person
does one problem and another person does another problem. Upload only one file per team. Make sure both names are written on the first page (above). Both partners will get the same score
. Partners do not have to be in the same section.
No late homework will be accepted
(1) Find the current I
1
in the following circuit where R
1
=R
2
=3Ω and R
3
=6Ω. (Hint: find I
2
, I
3
and I
4
, first and I
1
=I
2
+I
3
+I
4
. Voltage on the wire at the top is 24v higher than that at the bottom) (
4 points
)
I2 = V/R1 = 24V/3Ω = 8A
I3 = V/R2 = 24V/3Ω = 8A
I4 = V/R3 = 24V/6Ω = 4A
I2+I3+I4= 20A
Answer Including Units: 20A
(2) In the circuit shown below, V
1
=4v, V
3
=3v. Find V
2
. (Hint, the voltage on the wire at the top is 10v higher than the voltage on the wire at the very bottom.) (
3 points
)
V = 10V
V1 = 4V
V3 = 3V
V2 = V - V1 - V3 = 3V
Answer Including Units: 3V
(3) This high performing solar panel by SunForce is 24” by 54”. Its maximum power output is 80W when placed under full noon sunlight. What is the efficiency of this panel? Watch your units. (Hint: Power of sunlight on earth at noon is about 1kW/m
2
). (
3 points
)
Area of Panel = 24 x 54 = 1296 in^2 —> 0.836 m^2
I = P/A = 80W / 0.836 m^2 = 95.694 W/m^2 Efficiency = I/Io = 95.694/1000 = 0.095694 → 9.569%
(4) (10 points)
Calculate:
a. The theoretical
power available in the wind blowing at 15 m/s through an area swept by a turbine blade similar to the one you designed in the lab (let diameter =7 inches), assume air density of 1.2 kg/m
3
(3 points)
P = ½ x 1.2 x A x V^3
A = pi r^2 = pi 3.5^2 = 12.25pi = 38.4845 in^2 → 0.02498 m^2 7 in = 0.1778 m
V = 15 m/s
P = 50.278 Watts
b. The maximum power
extractable according to the Betz limit (2 points)
Betz limit = 59.3% Max power = 59.3% of 50.278 Watts = 29.815 Watts
c. What diameter wind turbine would be needed to power a small home installation, which might require 8 kW? For the Bay Area 5 m/s is a typical average wind speed. Assume a typical efficiency. Does this seem like a reasonable solution?
(5 points)
P = ½ x 1.2 x A x V^3 x efficiency reasonable efficiency seems like maybe 20%
8000 W = ½ x 1.2 x A x 5^3 x 0.2
A= 533.333 m = pi R^2
R = 7.52 m
D = 13.04 m Typical wind turbine blades are 35-36 meters long meaning the diameter is about 70 meters of a typical wind turbine. We calculated that a turbine with the diameter of 13.04 meters would be able to supply enough power to a small home installation. This would mean we believe it is a reasonable solution because 13.04 is a lot less than the normal 70 meter wind turbine. It is estimated that regular sized wind turbines can generate 840,000 kW of energy per month at 40% efficiency so our 13 meter blade
should be able to do 8000kW even when we said the efficiency was 20%
“How Many Homes Can an Average Wind Turbine Power?” How Many Homes Can an Average Wind Turbine Power? | U.S. Geological Survey
, www.usgs.gov/faqs/how-many-homes-can-average-wind-turbine-power#:~:text=At%20a
%2042%25%20capacity%20factor,than%20940%20average%20U.S.%20homes. Accessed 6 Mar. 2024. (5) (10 points)
Using SolidWorks (or other solid modeler of your choice), reproduce a vase similar to the one shown below. You are encouraged to create your own design
by changing the shape and size of the cross sections on each plane; a minimum of
5 planes
should be used. Figures 1 and 2 show a side view and isometric view of a vase with 0.01 in-thick walls. Hollow your vase using the Shell command. Print out a 2D view like figure 1 to show the 5 reference planes (4 points) and a 3D view of the vase as shown in Figures 2 and 3 (6 points). Figure 4 (rendered model) is not required.
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